Difficulty: Easy
Correct Answer: Residual (low-temperature) resistivity increases because Cu atoms act as defect scatterers
Explanation:
Introduction / Context:
Alloying modifies electron scattering in metals. Even small amounts of substitutional impurities introduce lattice disorder, which affects the electrical resistivity. This question focuses on how adding copper to nickel influences low-temperature (residual) resistivity and the general behavior explained by Matthiessen’s rule.
Given Data / Assumptions:
Concept / Approach:
Matthiessen’s rule states that total resistivity ρ(T) ≈ ρ_residual + ρ_phonon(T). Impurity atoms break translational symmetry and act as scattering centers even at T → 0, giving a finite ρ_residual. Therefore, adding Cu increases ρ_residual. At ordinary temperatures, total resistivity typically increases as well because the added residual term adds to the phonon term.
Step-by-Step Solution:
Introduce impurities → enhanced electron scattering independent of temperature.This raises ρ_residual (T → 0 limit).Therefore, compared with pure Ni, Ni-Cu alloy exhibits higher resistivity, with the clearest signature at low temperature.
Verification / Alternative check:
Experimental curves of ρ(T) for dilute Ni-Cu alloys show an upward shift of the entire ρ(T) curve and a finite intercept at T = 0 proportional to impurity concentration.
Why Other Options Are Wrong:
“Resistivity decreases” ignores defect scattering. “Remains the same” contradicts alloy scattering physics. “Thermal resistivity decreases” is unsupported. “Becomes zero” is impossible in normal metals.
Common Pitfalls:
Final Answer:
Residual (low-temperature) resistivity increases because Cu atoms act as defect scatterers
Discussion & Comments