Difficulty: Medium
Correct Answer: Field inside the cavity must be stronger than the field in the core
Explanation:
Introduction / Context:
Air cavities in magnetic materials are common in sensors and magnetic circuit analysis. Because flux density B relates to field strength H through material permeability, ensuring a specified B inside a cavity requires understanding how H differs across materials.
Given Data / Assumptions:
Concept / Approach:
Since permeability in air is μ0 and in core is μ0 * μr (μr > 1), the same B requires larger H in the lower-permeability region. Thus, to keep B_cav equal to B0, the magnetic field strength in the cavity must be larger than that in the core by a factor approximately μr.
Step-by-Step Solution:
Set equality of desired flux densities: B_cav = B_core = B0.Use constitutive relations: μ0 * H_cav = μ0 * μr * H_core.Cancel μ0 and solve: H_cav = μr * H_core.Conclusion: The cavity requires a stronger H than the surrounding core to achieve the same B.
Verification / Alternative check:
Finite-element simulations of small air gaps in magnetic circuits show elevated H inside the gap relative to the core for continuous B across the interface (normal component of B is continuous neglecting surface currents).
Why Other Options Are Wrong:
Equal fields would yield B_cav < B_core. Weaker field inside the cavity would reduce B further. “Arbitrary” and “zero” ignore constitutive physics.
Common Pitfalls:
Final Answer:
Field inside the cavity must be stronger than the field in the core
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