Difficulty: Easy
Correct Answer: NAND
Explanation:
Introduction / Context:
Recognizing a gate from its qualitative behavior is a key digital logic skill. The description says a LOW on any input inhibits the signal but produces a HIGH output regardless of the other inputs. This strongly hints at the inversion of an AND function, which is the NAND gate.
Given Data / Assumptions:
Concept / Approach:
The NAND truth function is Y = NOT(A * B * …). For NAND, the output is LOW only when all inputs are HIGH. If any input is LOW, the product A * B * … equals 0, so NOT(0) = 1 → output HIGH. Hence a LOW on an input 'inhibits' the low-output condition and produces HIGH, matching the description.
Step-by-Step Solution:
Verification / Alternative check:
Compare to AND: any LOW makes output LOW (contradicts the statement). Compare to OR: any HIGH makes HIGH (doesn’t mention LOW causing HIGH). Compare to NOR: any HIGH causes LOW (opposite behavior). Thus only NAND fits.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing NAND with NOR; remember NAND inverts AND (only all HIGH gives LOW), while NOR inverts OR (any HIGH gives LOW).
Final Answer:
NAND
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