Truth table size: For a four-input logic circuit (4 independent binary inputs), how many rows/entries are required in the complete truth table?

Difficulty: Easy

Correct Answer: 16

Explanation:


Introduction / Context:
Truth tables enumerate all possible input combinations and the resulting output(s). The size grows exponentially with the number of inputs, a key reason minimization tools (like Karnaugh maps or Boolean algebra) are important for larger systems.


Given Data / Assumptions:

  • Number of inputs n = 4.
  • Each input is binary (0 or 1).
  • We seek the number of unique rows in the truth table.


Concept / Approach:
For n binary variables, the number of distinct combinations is 2^n. Each combination corresponds to one row of the truth table. Thus, for four inputs, the table must have 2^4 entries covering all permutations from 0000 to 1111.


Step-by-Step Solution:

Let n = 4.Compute 2^n = 2^4.2^4 = 16 unique input combinations → 16 rows.


Verification / Alternative check:
List a subset to verify: 0000, 0001, 0010, …, 1111. Counting from 0 to 15 in binary gives exactly 16 combinations, confirming the result.


Why Other Options Are Wrong:

  • 4 or 8 or 12: Do not equal 2^4; they miss some combinations and would yield an incomplete truth table.


Common Pitfalls:
Confusing the number of inputs with the number of outputs or forgetting the exponential growth rule 2^n. This error leads to incomplete testing in design and verification.


Final Answer:
16

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