If p^x = q, which logarithmic relation is correct?

Introduction / Context:
Exponentials and logarithms are inverses. Translating p^x = q into a logarithmic statement tests understanding of this inverse relationship.

Given Data / Assumptions:
p > 0, p ≠ 1, q > 0; p^x = q.

Concept / Approach:
By definition, log base p of q equals the exponent x that raises p to q.

Step-by-Step Solution:

Why Other Options Are Wrong:
They mismatch positions of base/argument or set the log equal to the base rather than the exponent.

Final Answer:
log_p q = x