Difficulty: Medium
Correct Answer: e = e0 − Cs * log10(σ′/σ0′)
Explanation:
Introduction / Context:Natural clays exhibit a near-linear relationship between void ratio e and the logarithm of effective stress σ′ over certain ranges. On unloading–reloading (swelling/recompression), the slope is the swelling (recompression) index Cs (often denoted Cr), smaller than the compression index Cc on the virgin line. Correct sign and form are essential for settlement back-analysis and preloading design.
Given Data / Assumptions:
Concept / Approach:On the swelling/recompression line, as σ′ increases above σ0′, e decreases; as σ′ decreases below σ0′, e increases. A negative sign in front of Cs * log10(σ′/σ0′) captures this behavior: if σ′ > σ0′, the log ratio is positive and e reduces; if σ′ < σ0′, the log ratio is negative and e increases (swells). Using Cs rather than Cc reflects the smaller slope during recompression.
Step-by-Step Solution:
Start from linear form: e = e_ref − S * log10(σ′/σ_ref).For swelling/recompression, S = Cs (typically Cs < Cc).Adopt reference (e0, σ0′): e = e0 − Cs * log10(σ′/σ0′).Check signs: for unloading (σ′ < σ0′), log term negative → e increases, matching swelling.Verification / Alternative check:Oedometer data plotted on e–log σ′ commonly shows a steep virgin slope Cc and a flatter recompression slope Cs; extrapolations with the above form fit measured points.
Why Other Options Are Wrong:
Common Pitfalls:Mixing natural vs base-10 logs; confusing Cs with Cc; applying the relation outside its valid stress range.
Final Answer:e = e0 − Cs * log10(σ′/σ0′)
Discussion & Comments