Difficulty: Easy
Correct Answer: Both shear strength and bearing capacity
Explanation:
Introduction / Context:The quick or boiling condition in cohesionless soils occurs when upward seepage reduces the effective stress to near zero. This is a critical stability issue beneath structures, cofferdams, and cutoffs where upward gradients can induce piping or heave. Recognizing the implications is vital for safe construction dewatering and filter design.
Given Data / Assumptions:
Concept / Approach:Effective stress principle states: sigma′ = sigma − u. As upward seepage increases u, effective stress falls. At the quick condition, sigma′ → 0, so shear strength τ = sigma′ tan φ → 0. Bearing capacity in sands depends on effective stress and friction angle; when sigma′ vanishes, capacity collapses and soil behaves like a fluidized suspension, unable to support loads.
Step-by-Step Solution:
Relate upward gradient to pore-pressure increase: higher i → higher u.When u ≈ sigma (total), sigma′ → 0.With sigma′ → 0 → τ ≈ 0 and bearing capacity → negligible.Verification / Alternative check:Field evidence shows heave and sand boils when gradients approach ic. Countermeasures include relief wells, filters, and increasing overburden to restore sigma′.
Why Other Options Are Wrong:
Common Pitfalls:Confusing the quick condition with liquefaction under cyclic loading; both reduce sigma′ but mechanisms differ (steady seepage vs cyclic pore-pressure buildup).
Final Answer:Both shear strength and bearing capacity
Discussion & Comments