VSWR from power readings — directional coupler example In the setup shown (forward power meter at point A reads 1 mW; reflected power meter at point B reads 110 μW), determine the Voltage Standing Wave Ratio (VSWR) on the line.
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A1.5
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B2
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C2.5
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D3
Answer
Correct Answer: 2
Explanation
Introduction / Context:VSWR quantifies mismatch on a transmission line. Using a directional coupler or dual-direction power meter, one can read forward power P_f and reflected power P_r, convert to the magnitude of the reflection coefficient |Γ|, and then compute VSWR. This is a standard test-bench task in RF labs.
Given Data / Assumptions:
- Forward power P_f = 1 mW at point A.
- Reflected power P_r = 110 μW at point B.
- Meters and coupler are properly calibrated; same reference impedance.
Concept / Approach:The power reflection coefficient is |Γ|^2 = P_r / P_f. Hence |Γ| = sqrt(P_r / P_f). VSWR is defined as (1 + |Γ|) / (1 − |Γ|) for 0 ≤ |Γ| < 1. After computing |Γ| from the given readings, plug into the VSWR formula to get the final ratio.
Step-by-Step Solution:
Compute ratio: P_r / P_f = 110 μW / 1 mW = 0.11.Find |Γ|: |Γ| = sqrt(0.11) ≈ 0.3317.Compute VSWR: VSWR = (1 + 0.3317) / (1 − 0.3317) ≈ 1.3317 / 0.6683 ≈ 1.992.Round to nearest listed value: approximately 2.Verification / Alternative check:Convert |Γ| to return loss: RL = −20 * log10(|Γ|) ≈ 9.58 dB. The VSWR corresponding to about 9.6 dB return loss is ~2:1, which corroborates the calculation.
Why Other Options Are Wrong:
- 1.5: corresponds to |Γ| ≈ 0.2, not 0.332.
- 2.5: implies |Γ| ≈ 0.429, larger reflection than measured.
- 3: implies |Γ| ≈ 0.5, much larger reflection.
Common Pitfalls:Using power ratios directly in VSWR without taking the square root for |Γ|; mixing dB and linear units; misreading μW vs mW.
Final Answer:2