Matched transmission line example: A line with characteristic impedance Z0 = 400 Ω is terminated by a pure resistance of 400 Ω. What are the reflected quantities (voltage, current, and power) at the load?

Difficulty: Easy

Correct Answer: zero

Explanation:


Introduction:
This problem checks recognition of a perfectly matched transmission line. When the load equals the characteristic impedance, reflections vanish. Understanding this is essential for power transfer and VSWR control in RF systems.


Given Data / Assumptions:

  • Characteristic impedance Z0 = 400 Ω.
  • Load resistance RL = 400 Ω (purely resistive).
  • Assume a linear, time-invariant, lossless or low-loss line.


Concept / Approach:

The reflection coefficient at the load is Γ = (RL − Z0) / (RL + Z0). If RL = Z0, then Γ = 0, leading to zero reflected voltage and current. Consequently, all incident power is delivered to the load (neglecting line loss), and VSWR = 1.


Step-by-Step Solution:

Compute Γ: Γ = (400 − 400) / (400 + 400) = 0 / 800 = 0.Reflected voltage Vr = Γ * Vi = 0.Reflected current Ir = −Γ * Ii = 0 (sign irrelevant when Γ = 0).Reflected power Pr ∝ |Γ|^2 * Pi = 0 → all available power is absorbed by the load.


Verification / Alternative check:

On the Smith chart, the matched point is the exact center; any rotation due to line length does not move the impedance because reflections are absent. Measurements with a directional coupler would show forward power only and reverse power at the noise floor.


Why Other Options Are Wrong:

  • Equal/half/double: imply a nonzero Γ; inconsistent with RL = Z0.
  • Zero voltage but nonzero current reflection: impossible for passive linear lines at match; both are zero when Γ = 0.


Common Pitfalls:

Confusing load match with conjugate match in reactive cases; here the impedances are purely real and equal, guaranteeing no reflections.


Final Answer:

zero

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