Difficulty: Easy
Correct Answer: zero
Explanation:
Introduction:This problem checks recognition of a perfectly matched transmission line. When the load equals the characteristic impedance, reflections vanish. Understanding this is essential for power transfer and VSWR control in RF systems.
Given Data / Assumptions:
Concept / Approach:
The reflection coefficient at the load is Γ = (RL − Z0) / (RL + Z0). If RL = Z0, then Γ = 0, leading to zero reflected voltage and current. Consequently, all incident power is delivered to the load (neglecting line loss), and VSWR = 1.
Step-by-Step Solution:
Compute Γ: Γ = (400 − 400) / (400 + 400) = 0 / 800 = 0.Reflected voltage Vr = Γ * Vi = 0.Reflected current Ir = −Γ * Ii = 0 (sign irrelevant when Γ = 0).Reflected power Pr ∝ |Γ|^2 * Pi = 0 → all available power is absorbed by the load.Verification / Alternative check:
On the Smith chart, the matched point is the exact center; any rotation due to line length does not move the impedance because reflections are absent. Measurements with a directional coupler would show forward power only and reverse power at the noise floor.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing load match with conjugate match in reactive cases; here the impedances are purely real and equal, guaranteeing no reflections.
Final Answer:
zero
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