Mode identification in a rectangular waveguide: If the electric field shows one half-wave variation across the narrow wall and two half-wave variations across the broad wall, what is the resulting dominant mode notation?
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ATM12
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BTE13
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CTE21
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DTM25
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ETE02
Answer
Correct Answer: TE21
Explanation
Introduction / Context:Rectangular waveguides label modes as TEmn or TMmn. The first index m counts half-wave variations across the broad dimension a, and the second index n counts half-wave variations across the narrow dimension b. Accurately mapping spatial variations to indices is a common exam task.
Given Data / Assumptions:
- Across the narrow side (b): one half-wave variation.
- Across the broad side (a): two half-wave variations.
- We are to provide the correct mode label.
Concept / Approach:
By convention, m corresponds to the broad dimension a and n to the narrow dimension b. Two variations across a imply m = 2; one across b implies n = 1. Because the statement refers to the electric-field pattern in a typical hollow guide, the appropriate family is TE. Therefore, the mode is TE21.
Step-by-Step Solution:
Assign indices from variations: m = 2 (broad), n = 1 (narrow).Select family: TE, as commonly discussed for such field distributions.Write the final mode: TE21.Confirm it matches the described field pattern.Verification / Alternative check:
Field sketches for TE21 exhibit two lobes along a and one along b, consistent with the description. Reference charts align with this notation.
Why Other Options Are Wrong:
- TM12 and TM25: wrong indices and family.
- TE13: implies three variations across b, not one.
- TE02: implies zero variations along a, which contradicts the given two.
Common Pitfalls:
Swapping a and b or forgetting which index maps to which dimension.
Final Answer:
TE21