Difficulty: Easy
Correct Answer: Their magnitudes are equal and they differ in phase by ±90°
Explanation:
Introduction / Context:Circular polarization (CP) is vital in satellite and radar links because it reduces sensitivity to orientation and can mitigate multipath. Knowing the exact amplitude and phase conditions that generate CP is a foundational skill in antenna engineering.
Given Data / Assumptions:
Concept / Approach:
Perfect CP requires equal magnitudes and a phase quadrature of ±90 degrees. The electric-field tip traces a circle with constant magnitude. Any amplitude inequality or phase offset other than ±90 degrees yields elliptical polarization; equal magnitudes with 0 degrees phase difference give linear polarization.
Step-by-Step Solution:
Let Ex = E0 cos(ωt) and Ey = E0 cos(ωt ± 90°).Equal magnitudes ensure the locus is a circle rather than an ellipse.A ±90° phase offset ensures the components are in perfect quadrature, maintaining constant amplitude while rotating.Hence, CP occurs if and only if both conditions hold.Verification / Alternative check:
Phasor diagrams show the resultant vector has constant magnitude and rotates uniformly. Laboratory polarizers and OMTs are designed to enforce these amplitude and phase constraints.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing CP with simply “two components present”; both amplitude equality and quadrature phase are mandatory. Also, forgetting that axial ratio equals 1 for perfect CP.
Final Answer:
Their magnitudes are equal and they differ in phase by ±90°
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