Question 1

In basic astronomy, the Moon that we see in the Earth's sky every night is best classified as which type of celestial body?

Accepted Answer

Introduction / Context: When we look up at the night sky, one of the most prominent objects we see is the Moon. Understanding what the Moon is, and how it differs from planets, stars, and the Sun, is a fundamental part of school-level astronomy. The Moon does not shine by its own light; it reflects sunlight and moves around the Earth in a regular orbit. This question asks you to correctly classify the Moon as a type of celestial body. Given Data / Assumptions: The Moon is seen regularly in the Earth's sky and goes through phases. Planets orbit stars like the Sun; stars generate their own light by nuclear fusion. Satellites are bodies that orbit planets or other larger bodies. The options offer planet, star, Sun, and satellite as possible classifications. Concept / Approach: A natural satellite is a celestial body that orbits a planet or other non-stellar object. The Moon orbits the Earth roughly once every 27 days relative to the stars and about every 29.5 days relative to the Sun, causing the familiar lunar phases. It does not produce its own light; instead, we see sunlight reflected from its surface. Planets, such as Earth or Mars, orbit a star and do not orbit another planet as their primary motion. Stars, like the Sun, generate their own light and heat through nuclear fusion reactions in their cores. The Sun is our local star, not the Moon. Therefore, the correct classification for the Moon is that it is a natural satellite of the Earth. Step-by-Step Solution: Step 1: Recall that the Moon orbits the Earth, completing an orbit in about one month. Step 2: Understand that a natural satellite is defined as a body that orbits a planet, such as moons orbiting Jupiter or Saturn. Step 3: Recognise that planets like Earth and Mars orbit the Sun and are not themselves satellites of another planet. Step 4: Note that stars generate their own light and energy through nuclear fusion, while the Moon merely reflects sunlight. Step 5: Observe that the Sun is a star, not a moon; it is much larger and at the centre of the Solar System. Step 6: Conclude that the Moon is a natural satellite of the Earth. Verification / Alternative check: Astronomy textbooks and educational diagrams of the Solar System typically show the Earth with the Moon orbiting around it, labelling the Moon as Earth's natural satellite. They list planets like Mercury, Venus, Earth, and Mars as separate bodies orbiting the Sun. They also explain that stars are distant luminous objects that generate their own light, while moons do not. The Sun is always labelled as a star at the centre of the Solar System, distinct from the Moon. These consistent representations across educational materials confirm that the Moon is correctly classified as a natural satellite of the Earth. Why Other Options Are Wrong: A planet that orbits the Sun independently like Earth and Mars is incorrect because the Moon's primary motion is orbiting the Earth, not directly orbiting the Sun as a planet. A star that generates its own light by nuclear fusion is wrong because the Moon does not produce its own light; it only reflects sunlight. The Sun itself seen from a different angle is incorrect because the Sun and the Moon are completely different bodies with different sizes, compositions, and behaviours. Common Pitfalls: Young learners sometimes confuse the Moon and the Sun because both appear as bright discs in the sky. Others may think that anything bright is a star. To avoid this confusion, remember that the Sun is our star, planets orbit the Sun, and moons or natural satellites orbit planets. The Moon belongs in the last category because it goes around the Earth. Keeping these definitions clear will help you classify celestial objects correctly in astronomy questions. Final Answer: The Moon that we see in the sky is A natural satellite that orbits the Earth.

Question 2

In basic botany, what is the main central root of many dicot plants called, from which smaller side roots arise?

Accepted Answer

Introduction / Context: Plants absorb water and minerals from the soil through their root systems, which can have different structures depending on the species. Understanding the basic types of root systems is an important topic in school-level botany. Many dicotyledonous plants, such as carrot and mustard, have a single main root that grows downward, with smaller branches arising from it. This question asks you to identify the correct botanical term for that main central root. Given Data / Assumptions: The question refers to the main central root of plants, especially dicots. Smaller side roots arise from this main root. Options include tap root, lateral roots, fibrous roots, and anchor root. We assume standard definitions from school botany textbooks. Concept / Approach: In a tap root system, there is one primary root called the tap root that grows vertically downward. From this main root, many secondary or lateral roots arise, which may further branch. This type of system is typical of many dicots. In fibrous root systems, seen in many monocots like grasses, there is no single dominant root; instead, many fine roots of similar size emerge from the base of the stem and spread in all directions. Lateral roots are the side branches that emerge from the tap root or primary root. While roots do help to anchor the plant, "anchor root" is not the standard name for the main central root in this context. Therefore, the correct term is tap root. Step-by-Step Solution: Step 1: Recall that dicot plants often have one main root growing downwards, with smaller side roots attached. Step 2: Remember that this main root is called the tap root, and it forms the basis of a tap root system. Step 3: Identify that lateral roots are the smaller side branches that grow out from the tap root or primary root. Step 4: Recognise that fibrous roots describe a system where many roots of similar size arise from the base of the stem without a single dominant tap root. Step 5: Note that "anchor root" is not the standard textbook term for this structure in basic botany. Step 6: Conclude that the main central root is correctly called the tap root. Verification / Alternative check: Botany diagrams of root systems clearly label the main descending root in a carrot or mustard plant as the tap root, with lateral roots branching off. Text descriptions of tap root systems explain how the primary root persists and thickens, sometimes storing food, as in carrots and radishes. In contrast, fibrous root systems are illustrated with many roots of equal thickness spreading out, typical of grasses and cereals. No authoritative botany text uses "anchor root" as the primary term for the main central root system. This confirms that tap root is the correct answer. Why Other Options Are Wrong: Lateral roots, the smaller side branches arising from a main root, are not the main central root; they are secondary roots branching from the tap root. Fibrous roots, many thin roots of similar size forming a dense network, describe a different type of root system in which there is no single dominant primary root. Anchor root, a general term without specific botanical definition here, is not the proper textbook label for the main central root in dicot plants. Common Pitfalls: Students may confuse the term "lateral root" with "main root" because both are parts of the root system. Another common mistake is to think that because roots anchor the plant, "anchor root" must be the correct term, even though it is not standard. To avoid these errors, remember that the main downward-growing central root in many dicot plants is called the tap root, and the smaller side branches are lateral roots. Fibrous roots describe an entirely different pattern with no single central root. Final Answer: The main central root of many dicot plants is called the Tap root, the main central root growing downward.

Question 3

In plant growth, the increase in thickness or girth of the stem or root (secondary growth) in woody plants is mainly due to the activity of which type of meristematic tissue?

Accepted Answer

Introduction / Context: Plants grow not only in length but also in thickness. The increase in length of roots and shoots is called primary growth, while the increase in girth or thickness of stems and roots, especially in woody plants, is called secondary growth. This thickening is important for providing mechanical support and for forming wood and bark. Different types of meristematic tissues are responsible for primary and secondary growth. This question asks which meristem mainly causes the increase in girth of stems and roots. Given Data / Assumptions: Meristems are regions of actively dividing cells in plants. Apical meristems are located at tips of roots and shoots. Lateral meristems include vascular cambium and cork cambium. Intercalary meristems occur at internodes or the base of leaves in some plants. The question refers specifically to increase in thickness or girth (secondary growth). Concept / Approach: Secondary growth in woody dicots and gymnosperms is primarily due to the activity of lateral meristems. The vascular cambium produces secondary xylem (wood) to the inside and secondary phloem to the outside, increasing the diameter of the stem or root. The cork cambium (phellogen) produces cork cells and part of the bark, contributing to the outer protective layers. Apical meristems, located at the tips of roots and shoots, are responsible for primary growth in length, not thickness. Intercalary meristems help in elongation of internodes, especially in grasses. The term "extra meristem" is not a standard classification in basic botany textbooks. Step-by-Step Solution: Step 1: Identify that the question is about increase in girth or thickness, which is secondary growth. Step 2: Recall that secondary growth is associated with lateral meristems such as vascular cambium and cork cambium. Step 3: Recognise that vascular cambium adds new layers of xylem and phloem, increasing stem and root diameter. Step 4: Understand that cork cambium produces protective cork cells, contributing to the outer layers of bark. Step 5: Note that apical meristems at root and shoot tips mainly increase length, not girth. Step 6: Observe that intercalary meristems primarily help in elongation of internodes in some monocots, not in thickening woody stems. Step 7: Conclude that lateral meristems are responsible for the increase in girth of stems and roots. Verification / Alternative check: Standard plant anatomy diagrams show a ring of vascular cambium inside the stem of a dicot plant. Over time, this ring produces successive layers of secondary xylem, forming annual rings in trees. Textbooks explain that secondary growth is absent or minimal in most monocots, which lack typical lateral meristems. They also emphasise that apical meristems drive elongation, while lateral meristems are associated with radial or lateral expansion. No credible source describes "extra meristem" as a distinct category. This evidence confirms that lateral meristem is the correct answer. Why Other Options Are Wrong: Apical meristem at the tips of roots and shoots is incorrect because it causes primary growth in length, not the thickening associated with secondary growth in woody stems and roots. Intercalary meristem located at internodes or leaf bases is wrong because it mainly contributes to elongation of segments in plants like grasses, not to overall increase in girth. Extra meristem, a non-standard term in basic botany, is not recognised as a category responsible for secondary growth in textbooks. Common Pitfalls: Students often remember only that meristems cause growth and may not differentiate between apical, lateral, and intercalary types. This can lead to confusion about which meristem does what. Another common mistake is to assume that "apical" means all growth, including thickness. To avoid this, remember "apical = tip = length" and "lateral = side = thickness." Linking these simple associations helps you correctly identify that lateral meristems, especially vascular cambium and cork cambium, are responsible for increase in girth. Final Answer: The increase in girth of stems and roots is mainly due to Lateral meristem, such as vascular cambium and cork cambium.

Question 4

In reproduction and heredity, if which mode of reproduction is involved, even greater genetic diversity will be generated in the offspring population?

Accepted Answer

Introduction / Context: Genetic diversity is a measure of how many different combinations of genes exist within a population. This diversity is important for evolution, adaptation, and long-term survival of species. Different modes of reproduction affect genetic diversity in different ways. Asexual reproduction usually produces offspring that are genetically very similar to the parent, while sexual reproduction combines genetic material from two parents. This question asks which mode of reproduction, when it occurs, generates greater genetic diversity among offspring. Given Data / Assumptions: Sexual reproduction involves the fusion of male and female gametes. Binary fission and vegetative propagation are forms of asexual reproduction. Asexual reproduction generally produces offspring almost identical to the parent. The question focuses on which process increases diversity most strongly. Concept / Approach: In sexual reproduction, offspring receive half of their genetic material from each parent. During meiosis, processes like crossing over and independent assortment shuffle genes, creating new combinations in gametes. When gametes fuse at fertilisation, they form zygotes with unique genetic combinations, leading to high genetic variability in the population. In binary fission, a single-celled organism divides into two cells with identical genetic material, resulting in clones. Asexual reproduction and vegetative propagation in plants likewise produce offspring that are genetically similar or identical to the parent, aside from occasional mutations. Therefore, it is sexual reproduction that greatly increases genetic diversity. Step-by-Step Solution: Step 1: Identify that sexual reproduction involves two parents and the fusion of their gametes. Step 2: Recall that during meiosis, chromosome crossing over and independent assortment create many possible gene combinations. Step 3: Understand that fertilisation combines two different sets of genes, further increasing the number of possible genetic combinations in offspring. Step 4: Recognise that binary fission simply copies the DNA and splits one cell into two cells with the same genetic information. Step 5: Note that vegetative propagation and other forms of asexual reproduction produce new individuals with the same genetic makeup as the parent. Step 6: Conclude that sexual reproduction is the mode that generates greater genetic diversity in a population. Verification / Alternative check: Biology textbooks emphasise that sexual reproduction increases variation, which is one of the main drivers of evolution by natural selection. They explain how meiosis and fertilisation introduce genetic recombination and new allele combinations. Population genetics models show that sexually reproducing populations tend to have higher levels of genetic variation than clonally reproducing ones. Examples from nature include the wide variety of traits seen in humans and other sexually reproducing animals, compared to near-uniform clones produced by some asexual organisms. These observations confirm that sexual reproduction is strongly linked to greater genetic diversity. Why Other Options Are Wrong: Binary fission in which one cell splits into two identical cells is incorrect because it produces genetically identical daughter cells, not diverse offspring. Asexual reproduction producing genetically identical clones is wrong because its main feature is genetic uniformity rather than diversity, except for rare mutations. Vegetative propagation using stems, roots, or leaves from one parent plant is a form of asexual reproduction that usually produces clones of the parent plant, not highly diverse offspring. Common Pitfalls: Students may mistakenly think that because asexual reproduction can produce many offspring quickly, it must also produce more diversity. However, the number of individuals is different from the variety of genetic combinations. Another pitfall is to overlook the role of meiosis and to think that sexual reproduction only doubles the number of genes, instead of mixing them in new ways. To avoid these errors, remember that diversity comes from mixing and recombination of genetic material, which is precisely what happens in sexual reproduction involving gamete fusion. Final Answer: Even greater diversity will be generated if Sexual reproduction involving fusion of gametes from two parents is involved.

Question 5

In basic chemistry of metals, which highly reactive metal is commonly stored under kerosene oil to prevent it from reacting with air and moisture?

Accepted Answer

Introduction / Context: Different metals vary widely in their reactivity with air, water, and other substances. Highly reactive metals can corrode or react violently if they come into contact with moisture or oxygen. To store such metals safely, chemists often keep them under oil so that air and water cannot reach them. This question asks which metal, among the options given, is so reactive that it is commonly stored under kerosene oil in school laboratories and basic chemistry demonstrations. Given Data / Assumptions: Options include copper, sodium, platinum, and gold. Sodium is an alkali metal; copper, platinum, and gold are less reactive or noble metals. Kerosene oil does not mix with water and forms a barrier against air. We assume standard school laboratory safety practices. Concept / Approach: Sodium is a soft, silvery alkali metal that reacts vigorously with water, producing sodium hydroxide and hydrogen gas, often with enough heat to ignite the hydrogen. It also reacts with oxygen in air to form oxides and peroxides. Because sodium is so reactive, it cannot be safely left exposed to air and moisture. Instead, it is stored under kerosene or other mineral oils, which cover the metal and prevent contact with water and oxygen. Copper is less reactive and can be stored in air without special precautions. Platinum and gold are noble metals that resist corrosion and do not require storage under oil. Step-by-Step Solution: Step 1: Recall that sodium is an alkali metal placed in Group 1 of the periodic table and is highly reactive with water and oxygen. Step 2: Remember that when sodium is dropped into water, it reacts vigorously, releasing hydrogen gas and forming a strong alkali (sodium hydroxide). Step 3: Understand that to prevent accidental contact with moisture and air, sodium is stored under kerosene oil in sealed containers. Step 4: Compare this with copper, which tarnishes slowly but does not react violently with water and is commonly stored in air. Step 5: Note that platinum and gold are very unreactive, often called noble metals, and are used in jewellery and laboratory equipment because they do not corrode easily. Step 6: Conclude that sodium is the metal that must be stored under kerosene oil. Verification / Alternative check: Chemistry textbooks regularly illustrate the reactivity series of metals, showing that alkali metals like lithium, sodium, and potassium are among the most reactive. Laboratory safety sections warn that sodium and potassium should be stored under oil to avoid dangerous reactions. Demonstrations in school often show sodium reacting with water, skittering on the surface and sometimes igniting. In contrast, copper is widely used in electrical wiring and utensils without special storage, and platinum and gold are valued precisely because they resist corrosion. This confirms that sodium is the correct answer. Why Other Options Are Wrong: Copper, a relatively unreactive transition metal, does not require storage under kerosene; it forms a protective oxide or patina but does not react violently with water. Platinum, a noble metal with high resistance to corrosion, is extremely unreactive and is safely stored in air; it is used in jewellery and laboratory apparatus. Gold, a noble metal often used in jewellery, is also highly resistant to corrosion and tarnish, so there is no need to store it under kerosene. Common Pitfalls: Students may confuse "valuable" or "rare" with "reactive," assuming that metals like gold need special storage because they are precious. In reality, gold’s value partly comes from its low reactivity and resistance to corrosion. Another common error is to forget that alkali metals are at the top of the reactivity series. A simple memory aid is that Group 1 alkali metals such as sodium and potassium are so reactive that they must be kept under oil, whereas noble metals like gold and platinum are stable in air. Final Answer: The highly reactive metal commonly stored under kerosene oil is Sodium, a very reactive alkali metal that reacts vigorously with water.

Question 6

In biology, asexual reproduction commonly occurs in which groups of organisms listed below?

Accepted Answer

Introduction / Context: Reproduction is the biological process by which living organisms produce new individuals. There are two main modes: sexual reproduction, involving fusion of gametes, and asexual reproduction, where offspring arise from a single parent without gamete fusion. Asexual reproduction is common in many simple organisms and in many plants. This question asks you to identify which groups of organisms commonly show asexual reproduction, emphasising the broad distribution of this mode among lower animals and plants. Given Data / Assumptions: Asexual reproduction includes processes like binary fission, budding, fragmentation, and vegetative propagation. Lower animals include simple invertebrates and unicellular organisms such as protozoa. Many plants can reproduce asexually through vegetative parts like stems, roots, and leaves. Higher animals such as mammals and birds usually rely on sexual reproduction. Concept / Approach: Asexual reproduction is widespread among simple organisms. Bacteria, protozoa, and some worms reproduce by processes like binary fission, budding, or fragmentation. Many plants reproduce asexually through vegetative propagation, using structures like runners, tubers, bulbs, and cuttings. This allows rapid multiplication of genetically identical individuals. In contrast, higher animals like mammals, birds, and most reptiles usually reproduce sexually and rarely show natural asexual reproduction. Therefore, the correct answer should acknowledge that both lower animals and many plants can reproduce asexually. Step-by-Step Solution: Step 1: Recall that asexual reproduction occurs frequently in bacteria, protozoa, and some simple animals such as hydra and planaria. Step 2: Remember that plants often use vegetative propagation, a form of asexual reproduction, to produce new individuals from stems, roots, or leaves. Step 3: Recognise that higher animals like mammals and birds rely almost exclusively on sexual reproduction and do not typically reproduce asexually in nature. Step 4: Evaluate option A, which restricts asexual reproduction only to plants, ignoring its occurrence in lower animals, and see that this is incomplete. Step 5: Evaluate options B and C, which limit asexual reproduction to only higher or only lower animals, both of which ignore plants. Step 6: Conclude that the most accurate statement is that asexual reproduction occurs in both lower animals and many plants. Verification / Alternative check: Biology textbooks describe binary fission in amoeba, budding in hydra and yeast, and fragmentation in planaria as examples of asexual reproduction in simple animals and other organisms. In the plant kingdom, vegetative propagation in potato (tubers), strawberry (runners), and Bryophyllum (leaf buds) are standard examples of asexual reproduction. These sources emphasise that asexual reproduction is common in lower organisms and plants. They usually mention that higher animals seldom, if ever, reproduce this way in nature. This consistent description confirms that both lower animals and plants are involved. Why Other Options Are Wrong: Only plants, with no occurrence in animals is incorrect because many lower animals and microorganisms also reproduce asexually through processes like fission and budding. Only higher animals such as mammals and birds is wrong because these animals primarily use sexual reproduction; asexual reproduction is not a typical natural strategy for them. Only lower animals such as some worms and protozoa is incomplete because it ignores the very common occurrence of asexual reproduction in plants. Common Pitfalls: Students may focus only on one set of textbook examples, such as amoeba or yeast, and conclude that asexual reproduction is only relevant to microorganisms. Others may remember vegetative propagation in plants but forget that some animals also use asexual methods. To avoid this, keep in mind that asexual reproduction is usually associated with lower levels of biological complexity and is common in both lower animals and plants. Higher animals, on the other hand, are primarily sexual reproducers. Final Answer: Asexual reproduction commonly occurs in Both lower animals and many plants that can reproduce without gamete fusion.

Question 7

How much time does a geostationary satellite, orbiting at about 35,790 km above the Earth's surface, take to complete one orbit around the Earth?

Accepted Answer

Introduction / Context: Geostationary satellites are used for communications, weather monitoring, and broadcasting because they appear to stay fixed above one point on the Earth's equator. This apparent "standing still" occurs because the satellite orbits the Earth at the same rate that the Earth rotates. To achieve this effect, the satellite must be placed in a specific orbit and must take a specific amount of time to complete one revolution. This question asks you to identify that orbital period. Given Data / Assumptions: The satellite is described as geostationary, meaning it appears stationary over one point on the equator. The orbital height is approximately 35,790 km above the Earth's surface. Geostationary orbits are circular and in the equatorial plane. We assume standard definitions of a day, a month, and a year. Concept / Approach: A geostationary satellite must have an orbital period equal to the Earth's rotational period about its axis, as measured relative to the distant stars. This period is about 23 hours 56 minutes, which is very close to the 24-hour solar day that we commonly use. By matching this period, the satellite remains above the same geographic point on the equator. If the satellite had a period of 12 hours or 30 days, it would move relative to the Earth's surface, and observers would see it drift across the sky. A period of 365 days corresponds to the Earth's orbit around the Sun and has no relation to a geostationary orbit. Step-by-Step Solution: Step 1: Recall that geostationary satellites appear fixed in the sky because their orbital period matches the Earth's rotational period. Step 2: Remember that the Earth rotates once about its axis in approximately 24 hours. Step 3: Understand that a satellite with a 24-hour orbit around the Earth in the equatorial plane will have an angular speed equal to the Earth's rotation. Step 4: Note that 12 hours would correspond to a satellite that circles the Earth twice per day, which would not remain stationary in the sky. Step 5: Recognise that 30 days and 365 days correspond roughly to the Moon's orbit and the Earth's orbit around the Sun, not to geostationary satellites. Step 6: Conclude that the correct orbital period for a geostationary satellite is 24 hours. Verification / Alternative check: Space agency documentation and physics textbooks state that geostationary satellites orbit at a radius of about 42,164 km from the Earth's centre, which corresponds to approximately 35,790 km above the surface. At this altitude, the gravitational pull and orbital speed result in a period of exactly one sidereal day, about 24 hours. Communication satellites like many television and weather satellites are placed in geostationary orbit for this reason. Observers on the ground see antenna dishes pointed at a fixed spot in the sky, confirming that the satellite's apparent position is constant, which is only possible with a 24-hour period. Why Other Options Are Wrong: 30 days, matching approximately one lunar month, is incorrect because a satellite with this period would not remain fixed above one point; it would wander relative to the Earth's rotation. 365 days, matching one revolution of the Earth around the Sun, is wrong because such a period has nothing to do with geostationary motion around the Earth and would place the satellite far away in space. 12 hours, matching half a day, is incorrect because a satellite with a 12-hour period would pass over the same point twice a day but would not appear stationary. Common Pitfalls: Some students confuse the various time scales in astronomy, mixing up the length of a day, a month, and a year. Others think that any satellite orbit can be called geostationary as long as it goes around the Earth, regardless of period. To avoid confusion, remember that "geo" refers to Earth and "stationary" means staying over the same spot, which can only happen if the satellite's orbital period matches the Earth's rotation: about 24 hours. Final Answer: A geostationary satellite takes 24 hours, matching one rotation of the Earth on its axis to complete one orbit.

Question 8

Astronomers have identified one of the most ancient known spiral galaxies, which existed about 11 billion years ago. What is the designation of this distant spiral galaxy?

Accepted Answer

Introduction / Context: Galaxies in the early universe provide important clues about how the large-scale structure of the cosmos formed and evolved. Discovering spiral galaxies at very great distances, corresponding to times billions of years in the past, helps astronomers understand when and how ordered spiral structures emerged. One such ancient spiral galaxy has been observed through gravitational lensing and detailed imaging, and it has a specific catalogue designation. This question checks whether you know the name associated with that distant spiral galaxy, thought to have existed about 11 billion years ago. Given Data / Assumptions: The galaxy is described as a spiral galaxy from about 11 billion years in the past. Options list similar designations: A1689 B01, A1689 B10, A1689 B20, and A1689 B11. These names follow a typical pattern used in galaxy cluster and lensing studies. We assume familiarity with the specific object named in popular astronomy news and articles. Concept / Approach: The galaxy in question has been widely reported in astronomy news as one of the earliest known spiral galaxies, with its light passing through a cluster called Abell 1689, which acts as a gravitational lens. The magnified and distorted image allowed astronomers to study its spiral structure in detail. The designation given to this object is A1689B11. The other options are similar-looking catalogue names but do not correspond to this particular ancient spiral galaxy. Recognising the correct designation is largely a matter of recall from reading or studying astronomy reports. Step-by-Step Solution: Step 1: Identify that the question refers to a specific well-known ancient spiral galaxy observed through gravitational lensing. Step 2: Recall that the galaxy was given the designation A1689B11 in scientific reports and news articles. Step 3: Compare this with the options provided, noting that A1689 B11 matches the designation when written with a space. Step 4: Recognise that A1689 B01, A1689 B10, and A1689 B20 are distractor options created by varying the last digits. Step 5: Understand that only A1689 B11 corresponds to the famous ancient spiral galaxy described in the question. Step 6: Select A1689 B11 as the correct answer. Verification / Alternative check: Popular science articles and astronomy press releases discussing this discovery describe A1689B11 as a spiral galaxy seen as it was roughly 11 billion years ago. The Abell 1689 cluster acts as a natural lens, bending and magnifying its light. Astronomers used high-resolution imaging and spectroscopy to confirm its spiral nature. The exact designation A1689B11 is repeated across these sources. The slight difference in spacing (A1689B11 versus A1689 B11) in various formats does not change the identity of the object. None of the other letter-and-number combinations listed in the options is associated with this well-known galaxy in the literature. Why Other Options Are Wrong: A1689 B01 is incorrect because this designation does not correspond to the specific ancient spiral galaxy widely reported as existing 11 billion years ago. A1689 B10 is wrong for the same reason; it is a distractor that changes the final digits of the known designation. A1689 B20 is also incorrect; while it looks similar, it is not the reported name of the ancient spiral galaxy described in the question. Common Pitfalls: Because the options look very similar, students may answer based on a vague memory of the pattern without noticing the exact final digits. This is a classic example of a recall-based question where attention to detail is crucial. A good strategy for such questions is to memorise not just the general format but the specific digits of well-known objects, especially when they are highlighted in textbooks or news. In this case, remembering that the last two digits are "11" in A1689B11 helps you avoid mixing it up with similar-looking catalogue numbers. Final Answer: The most ancient spiral galaxy described in the question is designated A1689 B11.

Question 9

In December 2015, NASA's Curiosity Mars rover reported high concentrations of which substance in Martian rocks and soils, helping scientists learn more about the planet's ancient wet environment?

Accepted Answer

Introduction / Context: NASA's Curiosity rover has been exploring the surface of Mars to understand the planet's geology and past environmental conditions, including whether it once had liquid water that could support life. One of the important discoveries made by Curiosity in December 2015 involved detecting unusually high concentrations of a particular substance in Martian rocks and soils. This substance is often associated with water-related processes on Earth and can preserve clues about past environmental conditions. The question asks you to identify that substance. Given Data / Assumptions: The discovery occurred in December 2015 and involved NASA's Curiosity rover. The context is learning about an ancient wet environment on Mars. Options include magnesium, cadmium, silica, and calcium. Silica is known to be associated with water-related processes and can form deposits like opal. Concept / Approach: Silica is a compound of silicon and oxygen (SiO2) and is a major component of many rocks and minerals on Earth, such as quartz. On Mars and Earth, elevated silica concentrations can form in environments where water has interacted with rocks, leading to chemical alteration and the possible precipitation of silica-rich deposits. Silica can sometimes preserve evidence of microbial life or other environmental features. Curiosity's discovery of high-silica deposits suggested that water had once interacted with these rocks, providing an important clue about Mars' ancient climate. Magnesium and calcium are also present in Martian rocks, but the 2015 discovery specifically highlighted silica. Cadmium is less relevant to the typical geochemistry of Mars in this context. Step-by-Step Solution: Step 1: Recall that the Curiosity rover was sent to study whether Mars ever had conditions suitable for life, including the presence of liquid water. Step 2: Remember that in December 2015, NASA announced that Curiosity had found unusually high levels of silica in some Martian rocks. Step 3: Understand that silica-rich deposits often form through chemical processes involving water, such as hydrothermal activity or long-term water-rock interaction. Step 4: Compare this with the other options: magnesium and calcium are common elements but were not the focus of that particular announcement, and cadmium is not prominently associated with the Curiosity findings. Step 5: Recognise that silica as a compound of silicon and oxygen fits the description of the substance mentioned in the question. Step 6: Conclude that silica is the correct answer. Verification / Alternative check: Press releases and scientific reports from NASA and associated research teams describe Curiosity's observations of high-silica rocks in areas such as the "Marias Pass" region of Gale Crater. They explain that these silica-rich deposits were identified using instruments on the rover, and they discuss how such deposits can form in the presence of water. Articles emphasise that understanding the origin of these silica concentrations could reveal whether the environment was once hospitable to microbial life. Magnesium, cadmium, and calcium are not highlighted in the same way in these December 2015 discoveries, confirming that silica is the substance referred to. Why Other Options Are Wrong: Magnesium, a light metal element, is present in rocks and minerals but was not the specific focus of the December 2015 announcement concerning high concentrations linked to an ancient wet environment. Cadmium, a toxic heavy metal, is not commonly mentioned in the context of Curiosity's major findings and is not central to interpretations of past Martian water. Calcium, a metal associated with carbonates, is important in some Martian minerals, but the question specifically refers to the well-publicised discovery of high silica content. Common Pitfalls: Because all the options are chemical elements or compounds known on Earth, students may guess based on familiarity rather than recalling the specific rover result. Some may associate calcium with limestone and water on Earth and mistakenly choose it. To avoid confusion, focus on what was highlighted in December 2015 reports: silica-rich rocks. Remember that silica is chemically SiO2 and is frequently discussed in relation to Curiosity's findings about ancient Martian environments. Final Answer: In December 2015, Curiosity found high concentrations of Silica, a compound of silicon and oxygen in Martian rocks and soils.

Question 10

Which layer of the Earth's atmosphere contains ionised particles that reflect or refract certain radio waves and thus make long-distance radio communication possible beyond the horizon?

Accepted Answer

Introduction / Context: When we use radio communication, especially over long distances, signals sometimes travel far beyond the line of sight of the transmitting antenna. This is partly because certain layers of the Earth's atmosphere can reflect or refract radio waves back toward the surface, allowing them to "bounce" around the globe. The layer primarily responsible for this effect is known as the ionosphere. Understanding which atmospheric layer plays this role is important in both basic geography and communication technology. Given Data / Assumptions: The atmosphere is divided into layers: troposphere, stratosphere, mesosphere, thermosphere, and ionosphere (which overlaps some of these by altitude). The ionosphere is a region where solar radiation ionises gas molecules. Radio communication can use sky-wave propagation when signals are reflected or refracted by the ionosphere. The options mention troposphere, thermosphere, ionosphere, and stratosphere. Concept / Approach: The ionosphere is not a separate layer like the troposphere or stratosphere but a region of the upper atmosphere, mostly within the thermosphere and mesosphere, where solar ultraviolet and X-ray radiation ionises atoms and molecules, creating charged particles (ions and free electrons. These charged particles interact with radio waves. Certain frequencies of radio waves are refracted or reflected back to Earth by the ionosphere, enabling long-distance communication that would otherwise be limited by the curvature of the Earth. The troposphere is where most weather occurs, the stratosphere contains the ozone layer, and the thermosphere is a hot upper layer, but the specific radio-reflective behaviour is associated with the ionised region called the ionosphere. Step-by-Step Solution: Step 1: Recall that long-distance radio communication can occur when radio waves bounce off a layer of the atmosphere and return to the Earth's surface. Step 2: Remember that the ionosphere is a region of ionised gases created by solar radiation, containing many free electrons and ions. Step 3: Understand that these free electrons can reflect or refract certain radio frequencies, especially in the high frequency (HF) band. Step 4: Recognise that the troposphere is mainly associated with weather and does not usually reflect HF radio waves in the same way. Step 5: Note that while the thermosphere overlaps with the ionosphere in altitude, the term ionosphere specifically refers to the ionised region used for radio reflection. Step 6: Conclude that the correct answer is the ionosphere. Verification / Alternative check: Physics and geography textbooks describe sky-wave propagation as the process in which radio waves are reflected by the ionosphere, allowing communication beyond line of sight. Diagrams of the atmosphere show the ionosphere overlapping the upper mesosphere and thermosphere, with labelled ionospheric layers (D, E, F) that influence radio wave behaviour. Communications engineering references likewise discuss how ionospheric conditions affect radio reception and how solar activity can enhance or disturb this region. These sources consistently point to the ionosphere as the key region for long-distance radio communication. Why Other Options Are Wrong: Troposphere, the lowest layer where weather phenomena occur, is incorrect because although it affects radio propagation in other ways, it is not the primary region responsible for reflecting HF radio waves over long distances. Thermosphere, the upper hot layer affected by solar radiation, overlaps the ionosphere in altitude but is a broader temperature-defined layer; the specific reflective effect is attributed to the ionised region called the ionosphere. Stratosphere, the layer containing the ozone layer above the troposphere, is wrong because it primarily blocks harmful ultraviolet radiation and does not play the main role in reflecting radio waves. Common Pitfalls: Students sometimes confuse the thermosphere and ionosphere because they overlap and both are influenced by solar radiation. Another common mistake is to think that any upper layer automatically reflects radio waves. To avoid confusion, focus on the word "ion" in ionosphere, indicating charged particles, which interact strongly with radio waves. Remember that ionised particles and free electrons in the ionosphere are what enable radio signals to travel far beyond the horizon. Final Answer: The layer that makes long-distance radio communication possible is the Ionosphere, a region of ionised gases that can reflect radio waves.

Question 11

Fruits preserved in cold storage chambers last longer because the low temperature reduces their metabolic activity and slows the rate of respiration of the fruits.

Accepted Answer

Introduction / Context: Cold storage of fruits is a common post harvest technology used to keep fruits fresh for a longer period of time. Consumers often notice that fruits kept in a refrigerator or cold store spoil more slowly than fruits kept at room temperature. This question tests your understanding of why low temperature extends the shelf life of fruits, focusing on the biological process of respiration rather than simple ideas like darkness or humidity. Given Data / Assumptions: Fruits are living tissues that continue to respire after harvest. Cold storage means the temperature is significantly lower than normal room temperature. We assume that no other major preservation chemicals are being added, so the main factor is temperature. Fruit quality is affected by the rate of ripening and the growth of microorganisms. Concept / Approach: After harvest, fruits are still alive and continue to carry out respiration. In respiration, stored sugars are broken down to release energy, carbon dioxide and water. This process is essential for the fruit cells but also leads to ripening and eventual senescence or ageing. The rate of respiration is strongly influenced by temperature. At lower temperatures, enzyme activity slows down and respiration rate decreases. When respiration slows, the ripening and ageing processes also slow, and fruits stay firm and edible for a longer time. Therefore the key reason for longer storage life in cold conditions is reduced respiration, not increased oxygen or darkness. Step-by-Step Solution: Step 1: Recall that fruits are living organs which continue to respire even after being picked from the plant. Step 2: Understand that respiration uses stored food in the fruit and produces energy, carbon dioxide and water, leading gradually to ageing and softening. Step 3: Remember that enzyme controlled reactions such as respiration are slower at low temperatures. Step 4: Recognise that in a cold store, the temperature is lowered to reduce respiration rate and thereby slow ripening and spoilage. Step 5: Match this reasoning with the option stating that the rate of respiration of the fruits is decreased at low temperature. Verification / Alternative check: In horticulture and food science, charts of respiration rate versus temperature show that climacteric fruits such as bananas, apples and mangoes respire rapidly at warm temperatures but much more slowly in cool conditions. Cold storage is carefully designed to maintain an optimum low temperature that is above the chilling injury level but low enough to slow metabolic activity. This scientific evidence supports the statement that reduced respiration is the main reason for extended shelf life in cold stores. Why Other Options Are Wrong: Option a suggests that exposure to humidity is increased, but high humidity alone does not guarantee longer life and can even encourage fungal growth if not controlled. Option b states that more oxygen is available, but excess oxygen could actually speed up respiration and spoilage rather than slow it. Option c claims that fruits last longer simply because they are stored in a dark place, but darkness by itself does not significantly slow respiration compared to temperature reduction. Common Pitfalls: Many learners think that fruits stop all biological activity after harvest, which is not true. Another common misconception is that darkness is the main factor in preservation, similar to how light affects some chemical reactions. In reality, the most important factor in cold storage is temperature control, which directly influences respiration rate and enzyme activity. Understanding the relationship between temperature and metabolism helps avoid these misunderstandings. Final Answer: Fruits last longer in cold storage because the rate of respiration of the fruits is decreased at low temperature.

Question 12

In basic physics of light and colour, a blackboard appears black in colour because of the way it absorbs and reflects visible light falling on its surface.

Accepted Answer

Introduction / Context: Colour perception in daily life is explained by the interaction between light and objects. A blackboard is a familiar classroom object that appears black, and understanding why it looks black helps clarify how absorption and reflection of light work. This question examines the basic idea that black objects absorb nearly all colours of visible light rather than reflecting them. Given Data / Assumptions: White light from a tube light or the Sun consists of many colours. Objects appear coloured based on which wavelengths of light they reflect and which they absorb. A blackboard is coated with a dark material designed to give a black appearance. The human eye sees an object because of the light reflected from it. Concept / Approach: When white light falls on an object, some wavelengths may be absorbed and others reflected. If an object reflects a particular colour strongly and absorbs other colours, the eye perceives that object as having the reflected colour. For example, a red surface reflects red light more and absorbs other colours. A black surface, however, absorbs most of the visible light that falls on it and reflects very little. Because almost no light is reflected back to the eye, the surface appears black. Therefore a blackboard appears black because it is a strong absorber of visible light, not because it reflects black light, which is not a separate colour in the visible spectrum. Step-by-Step Solution: Step 1: Recall that black colour indicates an absence of reflected visible light reaching the eye. Step 2: Understand that a blackboard surface is designed to absorb most of the visible light incident on it. Step 3: Note that if an object reflected all colours of visible light equally, it would look white, not black. Step 4: Recognise that the idea of reflecting black colour is misleading because black corresponds to almost no reflected light. Step 5: Conclude that the correct explanation is that the blackboard absorbs almost all colours of visible light and reflects very little light. Verification / Alternative check: Experiments in an optics laboratory show that black surfaces heat up more in sunlight because they absorb a wide range of wavelengths rather than reflecting them. This is why black objects often feel hotter in the Sun compared to white objects. This absorption behaviour matches the explanation that black materials take in most of the light energy and reflect little back to the observer. Thus the black appearance of a blackboard is consistent with strong absorption of visible light. Why Other Options Are Wrong: Option a suggests that the blackboard reflects black colour, but black is the absence of visible light and is not a colour that can be reflected in the usual sense. Option b states that it absorbs only black colour, which is incorrect because black is not a specific wavelength that can be selectively absorbed; instead, many wavelengths are absorbed. Option c claims that it reflects all colours, which would make the board appear white or very bright rather than black. Common Pitfalls: Students sometimes imagine black as a special colour that is emitted or reflected, similar to red or blue, which leads to confusion. Another common mistake is to think that white and black are themselves single colours instead of combinations of reflection and absorption. Remembering that white corresponds to reflection of most wavelengths and black corresponds to absorption of most wavelengths helps avoid these errors. Final Answer: A blackboard appears black because it absorbs almost all the colours of visible light and reflects very little light to the eye.

Question 13

In physics, energy from the Sun travels through the vacuum of space to the Earth mainly by which mode of heat transfer?

Accepted Answer

Introduction / Context: The Earth receives a continuous supply of energy from the Sun, which drives weather, climate and life processes. Understanding how this energy travels through the almost empty space between the Sun and the Earth is a basic concept in physics and geography. This question focuses on identifying the correct mode of heat transfer responsible for this energy journey. Given Data / Assumptions: Space between the Sun and the Earth is nearly a vacuum, with extremely low matter density. Heat can be transferred by conduction, convection or radiation. Conduction and convection normally require matter such as solids, liquids or gases. Electromagnetic waves such as light and infrared radiation can travel through a vacuum. Concept / Approach: Conduction is the transfer of heat through direct contact between particles in a solid or between solids in physical contact. Convection is the transfer of heat by the movement of fluids such as liquids or gases. Both these processes require substantial matter. In contrast, radiation is the transfer of energy through electromagnetic waves that do not need a medium. Solar energy reaches the Earth mainly as visible light, infrared and other forms of electromagnetic radiation. Therefore, radiation is the only mode of heat transfer that can account for the energy travelling through space from the Sun to the Earth. Step-by-Step Solution: Step 1: Recall the three modes of heat transfer: conduction, convection and radiation. Step 2: Note that conduction requires direct contact between particles of matter and is most effective in solids. Step 3: Understand that convection requires a fluid such as air or water moving and carrying heat with it. Step 4: Recognise that space between the Sun and the Earth is nearly a vacuum, so conduction and convection cannot be the main processes. Step 5: Conclude that energy must travel by radiation, in the form of electromagnetic waves, which can move through a vacuum. Verification / Alternative check: Solar radiation is often measured in terms of solar constant and is described as electromagnetic radiation spanning ultraviolet, visible and infrared ranges. Satellites outside the atmosphere also receive this radiation, proving that it does not require air or any other medium. The greenhouse effect and climate models are based on absorption and emission of this radiative energy. All of these observations are consistent with radiation being the mode of heat transfer from the Sun to the Earth. Why Other Options Are Wrong: Option a, conduction, cannot explain heat transfer across the vacuum of space because there is no continuous material medium connecting the Sun and the Earth. Option b, convection, occurs within fluids like air and water but cannot operate across empty space where there is no medium to move. Option d, modulation, is a communication term that refers to varying a carrier wave to transmit information and is not a basic mode of heat transfer. Common Pitfalls: A common misunderstanding is to assume that because there is some thin solar wind and particles in space, conduction or convection may still play a major role. In reality, the density is so low that these effects are negligible compared with radiation. Another pitfall is confusing radio communication technology with energy transfer processes. Keeping the definitions of conduction, convection and radiation clear prevents such mistakes. Final Answer: Energy from the Sun reaches the Earth mainly by Radiation.

Question 14

In soil science, the downward transfer of dissolved minerals from the topsoil to the subsoil through soil water is called what?

Accepted Answer

Introduction / Context: Farmers and soil scientists study how water and dissolved substances move through soil layers, because this movement affects fertility and crop yield. When minerals are washed down from the topsoil to deeper layers, the nutrient content of the upper layer can decrease. This question asks you to identify the correct term for this particular process in soil science. Given Data / Assumptions: There is a distinct topsoil layer rich in organic matter and nutrients. Soil water can move downwards under the influence of gravity. Minerals can dissolve in water and be carried from one layer to another. We focus on the removal of minerals from the topsoil and their transport to subsoil. Concept / Approach: Percolation refers broadly to the movement or filtering of water through porous material such as soil. When water carrying dissolved minerals moves downward and removes those minerals from the topsoil, the process of loss of soluble nutrients is termed leaching. Leaching can reduce soil fertility in the upper layers and is a concern in areas with heavy rainfall or excessive irrigation. Conduction is a physics term for energy transfer and does not apply to this soil process. Transpiration is the loss of water vapour from plant leaves, not mineral movement in soil. Step-by-Step Solution: Step 1: Identify that the question mentions transfer of minerals from topsoil to subsoil through soil water. Step 2: Recall that percolation is mainly the movement of water itself through soil pores. Step 3: Recognise that when minerals dissolve in this moving water and are carried downward, the nutrient loss is called leaching. Step 4: Note that conduction is related to heat transfer, and transpiration is water loss from leaves, so they do not match the soil process described. Step 5: Choose leaching as the correct term for the process of minerals being washed out of the topsoil by downward moving water. Verification / Alternative check: Agriculture and soil science textbooks define leaching as the removal of soluble materials such as nitrates, potassium and other salts from the soil by percolating water. Examples are often given from high rainfall regions where nutrients are leached from the surface horizon to deeper horizons, sometimes leading to poor crop performance unless fertilisers are applied. The term percolation is reserved for water movement alone, without emphasising nutrient loss. This supports leaching as the correct answer. Why Other Options Are Wrong: Option a, percolation, refers to the general downward movement of water but does not specifically denote the loss of dissolved minerals from the topsoil. Option b, conduction, is a process of heat or electricity transfer and is unrelated to soil water and mineral movement. Option d, transpiration, describes water vapour loss from plant foliage, not mineral transfer in the soil profile. Common Pitfalls: Learners often confuse percolation and leaching because both involve water moving through soil. The key difference is that leaching emphasises the removal of dissolved substances, especially nutrients. Another pitfall is picking a familiar sounding term like conduction without checking its meaning in context. Carefully distinguishing the role of water alone versus water carrying dissolved minerals helps avoid such errors. Final Answer: The downward transfer of dissolved minerals from topsoil to subsoil by soil water is called Leaching.

Question 15

In the biofortification technique used in modern plant breeding, breeders mainly aim to overcome which type of nutritional problem in human populations?

Accepted Answer

Introduction / Context: Biofortification is an important concept in agricultural science and public health. Many people, especially in developing countries, consume enough calories but lack essential micronutrients such as iron, zinc or vitamin A. Plant breeders have developed strategies to increase the nutritional content of crops to address these hidden hunger problems. This question checks whether you understand the main goal of biofortification in plant breeding. Given Data / Assumptions: Biofortification is carried out through conventional breeding or biotechnology methods. Target crops include staples such as rice, wheat, maize and sweet potato. Problems such as insect pests and plant diseases are addressed by other breeding objectives like resistance breeding. The focus here is human nutritional quality, not just crop yield. Concept / Approach: Biofortification means improving the nutritional quality of food crops by increasing the content of vitamins and minerals in the edible parts. For example, breeding rice with higher iron and zinc content or sweet potato with higher beta carotene content. This approach aims to combat deficiencies of micronutrients and vitamins in populations that rely heavily on a few staple foods. While pest resistance and disease resistance are important breeding goals, they are not the primary focus of biofortification. Biofortified crops help reduce hidden hunger and associated health problems such as anaemia and impaired immunity. Step-by-Step Solution: Step 1: Recall that biofortification is about improving the nutrient content of crops, especially micronutrients. Step 2: Identify micronutrient deficiencies such as lack of iron, zinc and vitamin A as common public health issues. Step 3: Recognise that breeding for insect resistance or disease resistance is usually listed under different breeding goals. Step 4: Compare the options and find the one that specifically mentions deficiencies of micronutrients and vitamins. Step 5: Select the option that matches this description as the correct purpose of biofortification. Verification / Alternative check: International programmes such as HarvestPlus and various national agricultural research institutes have developed biofortified varieties like iron rich beans, zinc rich wheat and provitamin A rich maize. Their goal statements explicitly mention reduction of iron deficiency anaemia and vitamin A deficiency in vulnerable populations. Documentation about these programmes confirms that overcoming micronutrient and vitamin deficiencies is the central aim of biofortification, not directly increasing total production or pest control. Why Other Options Are Wrong: Option a, loss due to insect pests, is addressed by breeding for insect resistance through different traits such as thicker cuticles, toxins or repellent compounds. Option b, decrease in food production, refers to yield improvement, which is a classical breeding goal but not the specific definition of biofortification. Option d, loss due to plant diseases, is handled by disease resistance breeding rather than by increasing micronutrient content. Common Pitfalls: Students sometimes think any useful improvement in plant traits through breeding can be labelled biofortification, which is too broad. Another common mistake is to confuse fortification, where nutrients are added during food processing, with biofortification, where nutrient levels are increased directly in the crop. Remembering that biofortification deals with micronutrients and vitamins within the plant itself helps keep the concept clear. Final Answer: In biofortification, plant breeders mainly aim to overcome deficiencies of essential micronutrients and vitamins in the diet.

Question 16

Choose the most appropriate answer: animals that are naturally active at night and rest during the day are known by which term?

Accepted Answer

Introduction / Context: Different animals have different daily activity patterns, often linked to light, temperature and predator prey relationships. Some animals are most active during the day, while others come out at night. Knowing the correct terms for these patterns is part of basic ecology and zoology. This question asks you to identify the word used for animals that are active mainly at night. Given Data / Assumptions: There is a standard term for animals active during daylight hours. There is a standard term for animals active during night hours. Parasites are defined by how they obtain food, not by time of activity. The options include one correct standard term and some distractors. Concept / Approach: Animals that are active during daylight are called diurnal. Examples include many birds and humans. Animals that are active in the night and rest during the day are referred to as nocturnal. Examples include owls, bats and many small mammals. Parasites are organisms that feed on a host and can have various activity patterns, so parasite is not a term for time based activity. Nacto diurnal is not a commonly used standard term in zoology and appears as a distractor in this question. Step-by-Step Solution: Step 1: Identify that the key phrase in the question is animals active at night. Step 2: Recall that diurnal animals are active in the day and sleep or rest at night. Step 3: Remember that nocturnal animals are active mainly in the night. Step 4: Recognise that parasites are defined by their feeding relationship with a host, not by the time of day. Step 5: Conclude that nocturnal is the correct term for animals active at night. Verification / Alternative check: School and college level biology texts describe nocturnal animals as those that have adaptations such as large eyes, enhanced hearing or special senses allowing them to function in low light. Examples include owls, foxes and some insects. Diurnal animals are described alongside them as active in full daylight. This confirms that nocturnal is the widely accepted term for night active animals, matching the requirement of the question. Why Other Options Are Wrong: Option a, diurnal, refers to animals that are active during the day, which is the opposite of what the question describes. Option c, parasites, focuses on the mode of nutrition and living on or inside a host, not on whether the animal is active by day or night. Option d, nacto diurnal, is not a standard scientific term and appears to be a confusing combination of nocturnal and diurnal, so it does not fit the clear definition required. Common Pitfalls: Learners sometimes mix up the words diurnal and nocturnal because both are used together in ecological descriptions. Another mistake is seeing a strange compound word such as nacto diurnal and assuming it must be a technical term. Focusing on the root noct, which relates to night, and diurn, which relates to day, helps remember the correct meanings. Final Answer: Animals that are active mainly at night are called Nocturnal animals.

Question 17

Choose the most appropriate answer: on a weather map, lines joining places that have the same temperature at a given time are called what?

Accepted Answer

Introduction / Context: Weather maps and climate charts often use special lines to show patterns such as temperature, pressure and rainfall across a region. Understanding the names of these lines helps in reading meteorological information correctly. This question focuses on the term used for lines connecting places with equal temperature values at a given time or for a given period. Given Data / Assumptions: Several different iso lines exist in geography and meteorology. Temperature, pressure and rainfall each have their own standard iso line names. We assume the map is showing air temperature measured at many stations. The question specifies equal temperature as the key variable. Concept / Approach: The prefix iso means equal. In meteorology, isotherms are lines drawn on a map that connect places with the same temperature. Isobars are lines connecting places with equal atmospheric pressure. Isohyets connect places with equal rainfall. Isomers is a term used in chemistry to describe compounds with the same molecular formula but different structures, not map lines. Therefore, the correct term for lines of equal temperature is isotherms. Step-by-Step Solution: Step 1: Identify that the question is about equal temperature on a map. Step 2: Recall that isotherms are defined as lines of equal temperature. Step 3: Recognise that isobars are lines of equal pressure and isohyets are lines of equal rainfall. Step 4: Note that isomers is unrelated and used in organic chemistry, not in cartography. Step 5: Select isotherms as the correct name of lines joining places with equal temperature. Verification / Alternative check: Geography and meteorology textbooks show weather maps where isotherms are drawn to show patterns of warm and cold regions. These maps help forecasters identify fronts and temperature gradients. Similarly, isobars on the same maps show pressure patterns that indicate high and low pressure systems. This consistent use across sources confirms that isotherms is the correct term for lines of equal temperature. Why Other Options Are Wrong: Option b, isohyets, refers to lines connecting places with equal rainfall for a specific period, often used in climatology rather than temperature mapping. Option c, isomers, describes molecules in chemistry and has nothing to do with geographic maps or temperature. Option d, isobars, denotes lines joining points with equal atmospheric pressure, not temperature, and is used mainly in weather forecasting for pressure systems. Common Pitfalls: Because all these terms begin with iso, students sometimes mix them up. A useful trick is to remember therm for temperature, bar for pressure and hyet for rainfall. Combining these roots with iso gives the correct meanings for isotherms, isobars and isohyets. Careful attention to the second part of the word avoids confusion in exams. Final Answer: Lines joining places of equal temperature are called Isotherms.

Question 18

In basic astronomy, approximately how many days does the Moon take to complete one revolution around the Earth with respect to the stars?

Accepted Answer

Introduction / Context: The motion of the Moon around the Earth is one of the most noticeable regular patterns in the sky. Understanding the approximate time the Moon takes to complete one revolution around the Earth helps in explaining phases of the Moon, tides and calendars. This question asks for the approximate period of revolution of the Moon with respect to distant stars, often referred to as the sidereal month. Given Data / Assumptions: The Moon orbits the Earth in an approximately elliptical path. Two different time periods are often mentioned: the sidereal month and the synodic month. The question options include values close to the actual sidereal period. We assume the standard school level value taught for one revolution around the Earth. Concept / Approach: The sidereal month is the time taken by the Moon to complete one full orbit around the Earth relative to distant stars, and this period is about 27.3 days. The synodic month, which is the time from one new moon to the next, is slightly longer at about 29.5 days because the Earth Moon system also moves around the Sun. In many basic astronomy questions, when the phrase revolve around the Earth is used without extra detail, it refers to the sidereal period of about 27.3 days, which is the correct choice here. Step-by-Step Solution: Step 1: Recall that the Moon orbiting the Earth has a sidereal period of around 27.3 days. Step 2: Remember that 29.5 days corresponds to the lunar month between similar phases, not strictly the orbital period with respect to stars. Step 3: Compare the given options and locate 27.3 days among them. Step 4: Recognise that the other options 26.3, 28.3 and 29.2 are approximations that do not match the standard sidereal value. Step 5: Choose 27.3 days as the best answer consistent with standard textbook knowledge. Verification / Alternative check: Astronomy references and encyclopaedia entries commonly state that the Moon completes one revolution around the Earth relative to the fixed stars in about 27.3 days. They also mention a synodic period of about 29.5 days for the lunar phases. Diagrams showing the orbit of the Earth and Moon around the Sun are used to explain why these two periods differ. These sources consistently list 27.3 days as the orbital period relative to the stars, confirming the correctness of the chosen option. Why Other Options Are Wrong: Option a, 26.3 days, is significantly shorter than the accepted sidereal month and does not match standard data. Option c, 28.3 days, is slightly longer than the sidereal period but still not the commonly quoted value. Option d, 29.2 days, is closer to the synodic month but does not exactly represent the well known 29.5 day phase cycle, and the question refers to a revolution around the Earth in the basic sense. Common Pitfalls: A common confusion is between the sidereal and synodic months. Learners sometimes remember only one number and then apply it to every question. Another pitfall is to choose a rounded value that looks familiar without checking whether the question is about orbital revolution or phase cycle. Carefully reading the wording and recalling that 27.3 days is the orbital period helps avoid this mistake. Final Answer: The Moon takes approximately 27.3 days to complete one revolution around the Earth with respect to the stars.

Question 19

In oceanography, the gently seaward sloping submerged surface that extends from the coast to the deeper ocean is called what?

Accepted Answer

Introduction / Context: The floor of the oceans is not flat but has several distinct features such as shelves, slopes, abyssal plains and ridges. Close to the continents, there is a relatively shallow and gently sloping area that extends from the shoreline towards the deep ocean. This question checks whether you know the correct term for this important coastal feature in oceanography and geography. Given Data / Assumptions: The feature described is gently sloping and extends seaward from the coast. It is relatively shallow compared with the deep ocean basins. Other features such as abyssal plains and ridges occur farther from the continent and at greater depths. We assume a basic knowledge of ocean floor topography. Concept / Approach: The continental shelf is the submerged extension of the continent, stretching from the low water line to a point where the slope becomes steeper. It is shallow, usually less than 200 metres deep, and has a gentle seaward gradient. Beyond the shelf lies the continental slope and then the continental rise, which leads down to the abyssal plains. Abyssal plains are very deep, flat regions of the ocean floor, and submarine ridges are long mountain chains under the sea. Since the question mentions a gentle seaward sloping surface from the coasts, it clearly refers to the continental shelf. Step-by-Step Solution: Step 1: Note that the feature is described as gentle, shallow and starting from the coast. Step 2: Recall that the continental shelf is the shallow submarine extension of the continent with a gentle slope. Step 3: Recognise that the continental rise is deeper and located beyond the slope, not directly adjacent to the shore. Step 4: Identify that abyssal plains are deep flat regions of the central ocean basins, not gentle coastal slopes. Step 5: Understand that submarine ridges are underwater mountain chains and do not match the gentle shelf description, so the correct answer is continental shelf. Verification / Alternative check: Standard diagrams of the ocean floor in geography and earth science textbooks show a cross section starting with the coast, then the continental shelf, followed by the continental slope, continental rise and finally abyssal plain. Labels on these diagrams confirm that the gentle seaward extension just off the coast is called the continental shelf. Fishing grounds and offshore resources are often associated with continental shelves, reinforcing their practical importance and name recognition. Why Other Options Are Wrong: Option b, continental rise, is a more gently sloping area that lies between the continental slope and the abyssal plain, deeper in the ocean, and does not start directly from the coast. Option c, abyssal plains, are large, deep and almost flat regions far from continents, not gentle seaward slopes near the shore. Option d, submarine ridges, are underwater mountain chains which rise from the seafloor and do not resemble a broad gentle shelf. Common Pitfalls: Learners sometimes confuse the sequence of shelf, slope and rise or think that all shallow regions near coasts are simply called shallow sea. Another mistake is to choose abyssal plains because the word plain suggests flatness, forgetting that abyssal refers to great depth, not shallow water. Remembering the cross section diagram of the continental margin helps keep the terms in the correct order. Final Answer: The gentle seaward sloping submerged surface from the coasts is called the Continental shelf.

Question 20

In the process of photosynthesis, the liberation of oxygen gas takes place mainly due to which specific reaction occurring in the chloroplasts?

Accepted Answer

Introduction / Context: Photosynthesis is the fundamental process by which green plants produce food and release oxygen into the atmosphere. A common question in biology asks from which substance the released oxygen actually originates. Understanding the source of this oxygen clarifies the role of water in the light dependent reactions of photosynthesis. This question focuses on identifying the correct step that produces oxygen gas. Given Data / Assumptions: Photosynthesis occurs in two main stages: light dependent reactions and light independent reactions. Water and carbon dioxide are the main raw materials in photosynthesis. Oxygen is released as a by product of the process. Carbohydrates are formed as the main food product. Concept / Approach: Experiments using isotopes have shown that the oxygen released in photosynthesis comes from water, not from carbon dioxide. In the light dependent reactions, water molecules are split by the energy of absorbed light in a process called photolysis. This splitting of water produces electrons, protons and oxygen gas. The electrons are used in the electron transport chain, the protons contribute to ATP and NADPH formation, and the oxygen is released as a by product. Hydrolysis of carbohydrates and reduction of carbon dioxide occur at different stages and do not directly liberate oxygen gas. Breakdown of chlorophyll is related to ageing and stress, not to normal oxygen evolution in photosynthesis. Step-by-Step Solution: Step 1: Recall that photosynthesis involves light dependent reactions in the thylakoid membranes and light independent reactions in the stroma. Step 2: Understand that in the light dependent reactions, water molecules are split in the presence of light energy. Step 3: Recognise that this splitting, called photolysis of water, produces oxygen gas as one of the products. Step 4: Note that reduction of carbon dioxide produces carbohydrates but does not release free oxygen gas. Step 5: Conclude that liberation of oxygen is due specifically to photolysis of water molecules in the light reactions. Verification / Alternative check: Isotope labelling experiments using water containing a heavy isotope of oxygen showed that the oxygen released during photosynthesis carries the isotope label, while oxygen in carbon dioxide does not. This confirms that water, not carbon dioxide, is the source of the evolved oxygen. Detailed diagrams of the Z scheme of photosynthesis also show water splitting at photosystem II with oxygen evolution. These findings support the conclusion that photolysis of water is responsible for oxygen liberation. Why Other Options Are Wrong: Option a, hydrolysis of carbohydrates, refers to breaking down complex sugars and would consume water rather than release oxygen gas. Option c, reduction of carbon dioxide, forms carbohydrates and uses electrons and protons, but it does not produce molecular oxygen. Option d, breakdown of chlorophyll, occurs mainly during leaf ageing and stress and is not part of the normal mechanism producing oxygen in photosynthesis. Common Pitfalls: Students sometimes assume that because carbon dioxide contains oxygen atoms, the released oxygen must come from carbon dioxide. This misconception is corrected by learning about water splitting and by studying the experimental evidence using isotopes. Another pitfall is to mix up hydrolysis and photolysis, which are both chemical terms but refer to different processes. Remembering that photolysis is driven by light and specifically splits water in photosynthesis helps avoid confusion. Final Answer: The liberation of oxygen during photosynthesis is due to photolysis of water molecules in the light reactions.

General Science Questions