Question 1

Fuel technology: Tetraethyl lead (TEL) is used as what? Recall its historical role in internal combustion engines. Choose the correct application.

Accepted Answer

Given data Chemical: Tetraethyl lead (TEL). Concept/Approach TEL was historically added to gasoline as an antiknock agent to raise octane and reduce engine knocking. Its use has been largely phased out due to toxicity and environmental impact. Final Answer Petrol additive (antiknock agent)

Question 2

Allotropy in elements: Diamond is an allotropic form of which element? Allotropes are different structural forms of the same chemical element with distinct physical properties. Choose the correct element.

Accepted Answer

Given data Diamond is being compared as an allotropic form. Concept/Approach Allotropy refers to different structural forms of the same element. Carbon exhibits prominent allotropes: diamond (sp3 lattice), graphite (sp2 sheets), graphene, fullerenes, etc. Step-by-step reasoning Diamond consists of a 3D tetrahedral network of carbon atoms (sp3 hybridization), giving it exceptional hardness and high thermal conductivity. Common pitfalls Confusing with silicon or germanium, which also form covalent networks but are not the substance of diamond. Final Answer Carbon

Question 3

Materials and hardness: What is considered the hardest naturally occurring substance on Earth in standard general-knowledge contexts? Answer based on conventional Mohs hardness scale used in examinations. Choose the correct substance.

Accepted Answer

Given data Asks for the hardest naturally occurring substance on Earth. Concept/Approach On the conventional Mohs scale, diamond is rated 10 (the highest). Though some lab or rare phases may approach/exceed diamond in specific properties, standard GK/competitive exams accept diamond as the correct response. Step-by-step reasoning Diamond's strong sp3 covalent bonding in a tetrahedral lattice yields exceptional hardness. Common pitfalls Choosing dense or precious metals (gold, platinum) which are not the hardest. Final Answer Diamond

Question 4

General Science — Instruments and Measurements Answer the following: A “chronometer” is a device used to measure _____.

Accepted Answer

Introduction / Context: In scientific and nautical contexts, the term “chronometer” refers to a highly accurate timekeeping instrument. Historically crucial for navigation at sea, marine chronometers allowed sailors to determine longitude by comparing local solar time with a reference time. Recognizing what a chronometer measures is a foundational general-science and general-knowledge skill tested in many competitive exams. Given Data / Assumptions: Keyword: chronometer (from Greek “chronos” = time). Domain: measurement instruments. Goal: identify the physical quantity measured. Concept / Approach: Etymology is a powerful tool: “chrono-” indicates time. Instruments like thermometer (temperature), barometer (pressure), speedometer (speed) are named similarly. A chronometer is not just any clock; it denotes high-precision time measurement, traditionally exceeding the accuracy of ordinary watches, especially under environmental stress (temperature, motion). Therefore, among the options, “time” is the correct quantity measured. Step-by-Step Solution: 1) Parse the stem: identify the instrument — chronometer.2) Apply morphology: chrono = time; meter = measure.3) Match to options: select “time.”4) Cross-check against historical usage (marine chronometers). Verification / Alternative check: Practical check: GPS-free navigation relied on a chronometer’s exact time to compute longitude differences. This usage confirms it measures time, not sound, color, or water waves. Why Other Options Are Wrong: colour contrast: Measured by colorimeters or spectrophotometers.sound waves: Measured in frequency/amplitude by oscilloscopes or sound level meters.water waves: Analyzed by wave gauges; unrelated to “chrono.” Common Pitfalls: Confusing the suffix “-meter” with any meter device without attending to the prefix. Always decode both parts to identify the quantity correctly. Final Answer: time

Question 5

Physics — Units and Frequencies Fill in the blank: “Kilohertz (kHz) is a unit that measures _____.”

Accepted Answer

Introduction / Context: Understanding SI-derived units and their practical applications is essential in basic physics and electronics. “Hertz” (Hz) is the unit of frequency, meaning cycles per second. “Kilohertz” (kHz) equals 10^3 hertz. In communications and radio engineering, kHz commonly specifies the frequency of electromagnetic waves, such as AM broadcast bands and various signaling systems. Given Data / Assumptions: Base unit: hertz (frequency = cycles per second). Scale: kilo- = 10^3 (1,000). Context examples: radio carriers, audio sampling lower ranges, and ultrasonic boundaries. Concept / Approach: Frequency describes how often a periodic event repeats per unit time. While many phenomena have frequencies (sound, mechanical oscillations), the option that most accurately links “kilohertz” in common usage to a measurable domain is “electromagnetic radio wave frequencies.” Other listed electrical quantities—power, voltage, resistance—are measured in watts, volts, and ohms respectively and do not use hertz as their unit. Step-by-Step Solution: 1) Decode units: Hz = 1/s; kHz = 1,000/s.2) Identify domain: radio communications typically specify carriers in kHz or MHz.3) Match to options: “electromagnetic radio wave frequencies” is correct.4) Exclude mismatched quantities: watts, volts, ohms involve different dimensions. Verification / Alternative check: Example: An AM station at 810 kHz broadcasts with a carrier whose frequency is 810,000 cycles per second—textbook use of kHz for EM waves. Why Other Options Are Wrong: power used by a current of one ampere: Power is volts * amperes, measured in watts.voltage: Measured in volts; not a rate.electric resistance: Measured in ohms; not a rate. Common Pitfalls: Mixing up acoustic frequency with electrical quantities. While sound has frequency in hertz, the best option provided explicitly mentions radio waves, aligning with standard phrasing for kHz. Final Answer: electromagnetic radio wave frequencies

Question 6

Physics — Units and Acoustics Answer the following item: “Decibel (dB) is the unit for measuring the _____.”

Accepted Answer

Introduction / Context: The decibel (dB) is a logarithmic unit used to express ratios of power or amplitude, most famously for sound intensity levels in acoustics. Because human hearing perceives loudness roughly on a logarithmic scale, the decibel conveniently compresses a very wide dynamic range (from rustling leaves to jet engines) into manageable numbers. Exams frequently check whether candidates know that dB, in everyday contexts, quantifies sound intensity or sound pressure level (SPL). Given Data / Assumptions: Quantity of interest: sound intensity/loudness level. Unit: decibel (dB), a dimensionless logarithmic unit. Common domain: acoustics, audio engineering, noise regulation. Concept / Approach: Sound intensity level L (in dB) is typically defined using ratios relative to a reference intensity or pressure. Although the decibel can be used in other fields (e.g., electronics, telecommunications) to denote power gain or loss, in general-knowledge questions the expected answer is “intensity of sound.” Options mentioning speed of light or radio frequency are mismatched, since those are measured in m/s and hertz respectively. “Intensity of heat” is not a standard physical quantity with decibel units. Step-by-Step Solution: 1) Identify domain signaled by the unit: dB → acoustics/audio in common usage.2) Recall: decibel expresses logarithmic magnitude of sound intensity/pressure relative to a reference.3) Select “intensity of sound” as the best match among options.4) Exclude options mapped to different base units (m/s, Hz) or nonstandard quantities. Verification / Alternative check: Everyday examples: 30 dB (quiet room), 60 dB (normal conversation), 100+ dB (concerts). These values confirm that decibels rate how loud a sound is perceived/recorded relative to a reference level. Why Other Options Are Wrong: speed of light: Measured in meters per second (approximately 3 * 10^8 m/s).radio wave frequency: Measured in hertz (Hz), kilohertz (kHz), megahertz (MHz).intensity of heat: Not a standard decibel application in physics. Common Pitfalls: Thinking “decibel = loudness only.” More precisely, it is a logarithmic ratio unit. Still, for general GK questions, “intensity of sound” is the accepted and correct response. Final Answer: intensity of sound

Question 7

PHYSICS & ASTRONOMY — Identify the quantity measured by the given unit.  Question: What physical quantity does a light-year measure?

Accepted Answer

Introduction / Context: A light-year is one of the most commonly used astronomical units. Despite the word “year,” it does not measure time. This question checks whether you can distinguish among speed, time, and distance units that often get confused in popular science. Given Data / Assumptions: The context is astronomy and interstellar scales. Light travels at a constant speed in vacuum, approximately 3 * 10^8 m/s. We are comparing different physical quantities: speed vs distance vs time. Concept / Approach: A light-year is defined as the distance that light travels in vacuum in one Julian year. Using speed * time = distance, the quantity must be distance. Astronomers prefer such large units because kilometres or metres become unwieldy across interstellar space. Step-by-Step Solution: Use relation: distance = speed * time.Speed of light c ≈ 3 * 10^8 m/s.Time for one year t ≈ 365.25 days = 365.25 * 24 * 3600 s.Distance d = c * t ≈ 9.46 * 10^15 m, which is by definition 1 light-year.Therefore, a light-year measures interstellar (stellar) distances. Verification / Alternative check: Convert to astronomical units: 1 ly ≈ 63,241 AU, again a distance figure. No speed or time appears as the final dimension, confirming that the unit represents length. Why Other Options Are Wrong: A) “speed of aeroplanes” — speed is length/time; light-year is length only.B) “speed of light” — that is measured in m/s; not light-years.D) “speed of rockets” — also speed, not distance.E) “time taken by light in one year” — that is simply one year, a time unit; light-year is distance. Common Pitfalls: Assuming the word “year” implies time. In compound units like “man-hours” or “light-years,” the second word does not always dictate the dimension. Always analyze via speed * time = distance. Final Answer: stellar distances

Question 8

BASICS OF UNITS — Choose the correct equivalence.  Question: One horsepower (hp) is equal to how many watts (W)?

Accepted Answer

Introduction / Context: Horsepower is a traditional unit of power still seen in automotive specifications. In SI, power is measured in watts. Converting horsepower to watts is a standard recall item bridging legacy and SI systems. Given Data / Assumptions: We are using the mechanical horsepower defined by James Watt for engines. SI base unit of power is the watt (W). No alternate metric horsepower is implied unless stated. Concept / Approach: Mechanical horsepower is defined exactly as 550 foot-pounds per second. Converting foot-pounds to joules and seconds gives a fixed value in watts. The widely standardized conversion is 1 hp = 745.7 W, rounded to 746 W for most exam purposes. Step-by-Step Solution: Start with definition: 1 hp = 550 ftlbf/s.1 ftlbf ≈ 1.3558179 J.So power = 550 * 1.3558179 J/s ≈ 746 W.Rounded value used in textbooks: 746 watts. Verification / Alternative check: Automotive conversions often use hp to kW: 1 kW ≈ 1.341 hp, hence 1 hp ≈ 0.7457 kW = 745.7 W → 746 W rounded. Why Other Options Are Wrong: B) 748 W — too high; not the accepted rounded value.C) 756 W — off by more than 1%.D) 736 W — close to metric horsepower (PS) confusion; mechanical hp is ≈ 745.7 W, metric horsepower is ≈ 735.5 W.E) 700 W — rough and incorrect. Common Pitfalls: Mixing mechanical horsepower with metric horsepower (PS). Always check which definition the question uses; standard school exams use 746 W. Final Answer: 746 watts

Question 9

BASICS OF UNITS — Identify the physical quantity.  Question: The unit "bar" is used to measure which physical quantity?

Accepted Answer

Introduction / Context: Everyday weather reports and many engineering tables use the unit “bar.” Recognizing what it measures helps connect meteorology, fluid mechanics, and instrumentation. Given Data / Assumptions: “Bar” is a non-SI unit widely used for pressures around atmospheric levels. Standard atmospheric pressure at sea level is close to 1 bar. We are distinguishing among scalar thermodynamic and electrical quantities. Concept / Approach: Pressure equals force per unit area. SI uses the pascal (Pa). By definition, 1 bar = 10^5 Pa, which is very close to 1 atmosphere (1.01325 * 10^5 Pa). Hence bar is a convenient rounded unit for atmospheric and process pressures. Step-by-Step Solution: Recall: 1 bar = 100,000 Pa.Atmospheric pressure at sea level ≈ 1.01325 bar.Therefore, “bar” measures pressure, often atmospheric or gauge pressures.Options linked to temperature, heat, current, or resistance are unrelated dimensions. Verification / Alternative check: Instrument dials on compressors or scuba gear often show pressure in bar alongside psi or kPa, reinforcing the interpretation. Why Other Options Are Wrong: A) Temperature is in K, °C, or °F.B) Heat is energy, measured in J or cal.D) Current is in ampere (A).E) Resistance is in ohm (Ω). Common Pitfalls: Confusing “bar” (pressure) with “bar” as a length of metal (shape), or mixing up atmospheric “atm” and “bar.” Remember the simple relation 1 bar = 10^5 Pa. Final Answer: atmospheric pressure

Question 10

MEASUREMENT OF TIME — Choose the most precise device.  Question: Very small time intervals are measured most accurately using which of the following?

Accepted Answer

Introduction / Context: Modern science and technology depend on ultra-precise timekeeping: GPS, telecommunications, and fundamental physics experiments all require nanosecond-level accuracy. This question targets your knowledge of which devices provide the highest precision for very small intervals. Given Data / Assumptions: We compare natural and engineered “clocks.” “Very small time intervals” implies sub-microsecond accuracy and stability. We ignore impractical cosmic distances or observational delays for daily measurement tasks. Concept / Approach: Atomic clocks use the quantized transition frequencies of atoms (commonly cesium or rubidium) as their fundamental standard. Because these frequencies are extremely stable, such clocks achieve extraordinary precision and are the official basis of the SI second. Quartz clocks are good for everyday use but drift more. Pulsars can be stable rotators, yet astronomical observations limit practicality and resolution in daily metrology. Step-by-Step Solution: Identify the target: maximum accuracy in short intervals.Note performance hierarchy: atomic > quartz > mechanical.Exclude astronomical sources (pulsars, white dwarfs) for precise lab-scale timing.Select: atomic clocks. Verification / Alternative check: The SI second is defined via the cesium-133 hyperfine transition frequency: time standards use this constant to realize extremely accurate intervals, validating atomic clocks as the gold standard. Why Other Options Are Wrong: A) White dwarfs are stars; not timing devices.B) Quartz clocks are less stable than atomic standards.D) Pulsars are precise but impractical for fine interval measurement in labs.E) Pendulum clocks are much less precise. Common Pitfalls: Equating regular astronomical phenomena with practical precision. Lab-grade timing requires controllable, accessible standards—hence atomic clocks. Final Answer: atomic clocks

Question 11

BASICS OF UNITS — Select the correct conversion.  Question: One joule equals how many ergs?

Accepted Answer

Introduction / Context: Joule (J) is the SI unit of energy, while the cgs unit is the erg. Converting between SI and cgs systems is a staple skill in physics and engineering fundamentals. Given Data / Assumptions: 1 J = 1 Nm and 1 N = 10^5 dynes; 1 m = 10^2 cm. 1 erg = 1 dynecm. We seek a pure numerical factor relating J and erg. Concept / Approach: Use base conversions systematically. Express the SI unit (Nm) in cgs (dynecm) and match to the definition of the erg. Careful tracking of powers of ten yields the final factor. Step-by-Step Solution: Start: 1 J = 1 Nm.Convert force: 1 N = 10^5 dynes.Convert length: 1 m = 10^2 cm.Therefore: 1 J = (10^5 dynes) * (10^2 cm) = 10^7 dynecm = 10^7 ergs. Verification / Alternative check: Reverse: 1 erg = 10^-7 J. This reciprocal relation consistently appears in reference tables and problem solutions. Why Other Options Are Wrong: A) 10^5 ergs — underestimates by 100x.B) 10^3 ergs — off by a factor of 10,000.D) 10^11 ergs — overestimates by 10,000.E) 10^9 ergs — incorrect scaling. Common Pitfalls: Losing track of powers when converting both force and length. Do them stepwise and multiply exponents: 10^5 * 10^2 = 10^7. Final Answer: 10^7 ergs

Question 12

ACOUSTICS — Identify the unit for the specified quantity.  Question: Which unit is commonly used to express the amplitude (level) of sound in practical measurements?

Accepted Answer

Introduction / Context: In acoustics, several related but distinct quantities appear: pressure amplitude, intensity, and sound level. Everyday instruments (sound level meters) typically report levels in decibels (dB), a logarithmic measure referenced to a standard threshold. This question tests recognition of the practical unit used to report how “loud” a sound is. Given Data / Assumptions: We focus on standard reporting of sound magnitude in practice. Decibel is a logarithmic ratio unit; coulomb is electric charge; “hum” is not a unit; “cycles” relates to frequency; pascal is pressure. Concept / Approach: Human hearing spans a vast dynamic range. Using a logarithmic scale (decibel) compresses this range into manageable numbers. While the underlying physical amplitude could be sound pressure in pascals, practical sound “amplitude” or level for environments, industry, and safety is expressed in dB SPL (sound pressure level), referenced to 20 μPa. Step-by-Step Solution: Recognize the real-world reporting convention: SPL in dB.Relate physical quantity: level relates to pressure amplitude via logarithmic formula.Eliminate unrelated electrical or non-units.Choose decibel as the standard practical unit. Verification / Alternative check: Noise regulations, workplace safety standards, and audio equipment specs all quote “85 dB,” “94 dB,” etc., confirming decibel as the everyday measure of sound magnitude. Why Other Options Are Wrong: B) Coulomb measures charge, not acoustics.C) “Hum” is a phenomenon, not a unit.D) “Cycles” label frequency counts; the SI form is hertz (Hz).E) Pascal is the base pressure unit; however, standard sound “amplitude” reporting is in decibel SPL. Common Pitfalls: Confusing raw pressure amplitude (Pa) with level reporting (dB). Exams usually expect “decibel” for practical sound amplitude/level. Final Answer: decibel

Question 13

NAVIGATION — Choose the correct application of the unit.  Question: A nautical mile is a unit of distance primarily used in which domain?

Accepted Answer

Introduction / Context: Nautical miles are fundamental in marine and air navigation. This unit ties distance directly to Earth’s geometry, simplifying charting and position calculations on a spherical surface. Given Data / Assumptions: 1 nautical mile (nmi) is defined as exactly 1852 m. It relates closely to latitude: 1 minute of arc along a meridian ≈ 1 nmi. Used with knots for speed (nautical miles per hour). Concept / Approach: Because route planning over Earth’s surface uses angular coordinates, a distance unit tied to arcminutes is convenient for sailors and pilots. Road transport uses statute miles or kilometres; astronomy uses parsecs/AU/light-years; boundary measurement is a legal process not tied to this unit. Step-by-Step Solution: Recall definition: 1 nmi = 1852 m.Note usage: marine and aviation navigation charts.Match domain: navigation is the primary application.Exclude domains using statute miles/km or astronomical units. Verification / Alternative check: Speed in navigation is “knots,” where 1 knot = 1 nmi/h, reinforcing that the unit belongs to navigation practice. Why Other Options Are Wrong: B) Road mile refers to statute mile ≈ 1609 m, not nautical mile.C) Astronomy uses AU, ly, or parsec.D) National boundaries are surveyed in various units, commonly km.E) City maps use km or metres for fine scale. Common Pitfalls: Equating all “miles.” Nautical mile is longer than the statute mile and is specialized for navigation. Final Answer: navigation

Question 14

SPEED UNITS — Identify the correct application.  Question: The knot is a unit of speed typically used for which of the following?

Accepted Answer

Introduction / Context: A “knot” is the standard speed unit in maritime navigation, defined as one nautical mile per hour. It is also widely used in aviation, but historically it comes from seafaring practice. This item checks recognition of the primary traditional domain. Given Data / Assumptions: 1 knot = 1 nmi/h, where 1 nmi = 1852 m. Ships and aircraft commonly report speeds in knots for navigational consistency. Waves (light or sound) use different speed descriptors and contexts. Concept / Approach: Because the nautical mile and knots form a pair, and because charts and routes were first standardized at sea, “ship” is the best-fit answer among the choices given. Although aeroplanes also use knots, the question typically expects the maritime association. Step-by-Step Solution: Recognize definition: knot = nmi per hour.Link to nautical domain: ships navigate using nautical miles.Select “ship.”Note that aviation also uses knots, but the origin is maritime. Verification / Alternative check: Bridge logs and maritime Automatic Identification System (AIS) display ship speeds in knots; flight instruments likewise show knots, but the traditional association remains nautical. Why Other Options Are Wrong: A) Aeroplanes do use knots, but the canonical association is maritime; the option set expects “ship.”B) Light waves have speed c in m/s, not knots.D) Sound waves are discussed in m/s or km/h.E) Trains use km/h or mph. Common Pitfalls: Overlooking that multiple domains use knots. In exam settings, choose the maritime answer unless the question specifies aviation. Final Answer: ship

Question 15

WEATHER INSTRUMENTS — Interpret the reading.  Question: If the barometer reading keeps going down, what is it generally an indication of?

Accepted Answer

Introduction / Context: A barometer measures atmospheric pressure. Interpreting rising and falling pressure helps forecast short-term weather. This question tests whether you can connect a persistent pressure drop to likely weather outcomes. Given Data / Assumptions: “Going down” means a sustained fall from the local mean pressure. Low pressure systems are associated with clouds, winds, and precipitation. We aim for the most general inference rather than a specific event in a specific climate. Concept / Approach: Falling barometric pressure indicates the approach or strengthening of a low-pressure area. Low pressure promotes air rising, cooling, and cloud formation, often leading to unsettled conditions such as storms. While rain is common, “storm” captures the broader, more definitive sign of significant weather. Step-by-Step Solution: Note relationship: pressure ↓ → low-pressure system.Low pressure → convergence and uplift of moist air.Uplift → condensation → clouds/precipitation → windy or stormy weather.Therefore, a falling barometer points to stormy conditions. Verification / Alternative check: Marine and aviation weather briefings flag rapidly falling pressure as a warning for gales or storms. Gradual minor drops may precede rainfall; a sharp drop often precedes severe weather. Why Other Options Are Wrong: A) Snow is a type of precipitation; pressure alone does not specify snowfall.C) Intense heat aligns with high pressure and clear skies in many regions.D) Rainfall can occur, but “storm” is the broader, more diagnostic outcome of a notable pressure fall.E) Clear skies correlate with rising or high steady pressure. Common Pitfalls: Thinking “rain” whenever pressure falls. The better general inference is deteriorating or stormy weather, which may include rain, winds, and thunderstorms. Final Answer: storm

Question 16

POWER & ENERGY — Identify the correct quantity.  Question: Kilowatt (kW) is a unit used to measure which physical quantity?

Accepted Answer

Introduction / Context: Power and energy are frequently confused in everyday language. Kilowatt (kW) and kilowatt-hour (kWh) appear on appliance labels and electricity bills, respectively. This question checks whether you can separate instantaneous rate (power) from accumulated quantity (energy). Given Data / Assumptions: Watt (W) is the SI unit of power; kilo- denotes 10^3. Energy in SI is joule (J); in power billing, energy is often reported in kWh. “Electricity” is a loose term and not a unit/quantity by itself. Concept / Approach: Power is the rate at which work is done or energy is transferred per unit time. 1 W = 1 J/s. Therefore, 1 kW = 1000 J/s. Energy over time uses watt-hours: energy (Wh) = power (W) * time (h). Distinguishing these clarifies why devices list kW (capacity/rating) while meters total kWh (consumption). Step-by-Step Solution: Identify quantity: kW = 10^3 watts.Recall: power P = energy/time.Therefore, kW measures power (rate), not energy.Relate: energy used E = P * t, often shown in kWh. Verification / Alternative check: If a heater is rated 2 kW and runs for 3 hours, energy = 2 kW * 3 h = 6 kWh. Rating is in kW (power), consumption is in kWh (energy), confirming the distinction. Why Other Options Are Wrong: A) Work (energy) is the result, measured in J or kWh, not kW.C) “Electricity” is not a unit; too vague.D) Current is measured in ampere (A).E) Energy is in joule or kilowatt-hour, not kilowatt. Common Pitfalls: Reading kW on a bill and assuming it is energy. Remember: kW (rate) vs kWh (amount). Final Answer: power

Question 17

General Science – Unit conversion (distance) Question: One kilometre (km) is equal to how many miles (mi)?

Accepted Answer

Introduction / Context: This question checks basic unit conversion between the metric system and the imperial/US customary system. Converting kilometres (km) to miles (mi) is common in travel, navigation, athletics, and everyday life, so remembering the standard factor helps you estimate distances accurately. Given Data / Assumptions: We want miles (mi) for a distance of exactly 1 kilometre (km). Use the standard conversion factor: 1 km ≈ 0.621371 mi. Options are rounded to two decimal places, so the nearest correct choice is required. Concept / Approach: To convert from kilometres to miles, multiply by the constant factor miles_per_km. The widely accepted factor is 0.621371. When options present rounded values, choose the one that reasonably approximates the precise result. Step-by-Step Solution: Let distance_km = 1.Use miles_per_km = 0.621371.Compute miles: miles = distance_km * miles_per_km.miles = 1 * 0.621371 = 0.621371.Round to two decimals for comparison with options: 0.621371 ≈ 0.62. Verification / Alternative check: Recall the inverse factor: 1 mile ≈ 1.609 km. Therefore, 1 km ≈ 1 / 1.609 ≈ 0.621, which matches 0.62 to two decimals. Why Other Options Are Wrong: 0.84: Too high; would imply 1 km is almost one mile, which is incorrect. 0.5: Too low; half a mile is about 0.805 km, not 1 km. 1.6: This is approximately km per mile, not miles per km. Common Pitfalls: Mixing up the direction of conversion factors (using 1.609 instead of 0.621 for km → mi) or rounding too aggressively. Keep two decimals for quick estimations. Final Answer: 0.62

Question 18

Basic Units – Identify the physical quantity measured in the nautical unit “fathom”.

Accepted Answer

Introduction / Context: A fathom is a traditional nautical unit commonly used in maritime navigation and oceanography. Understanding which quantity it measures helps interpret nautical charts and marine reports, especially for safe anchoring and dredging operations. Given Data / Assumptions: We must identify the physical quantity associated with “fathom”. Fathom is primarily used at sea. Typical equivalence: 1 fathom = 6 feet ≈ 1.8288 m. Concept / Approach: In marine contexts, fathoms are used to report water depth below the waterline or chart datum. While “distance” is a general term, the specialized application of “fathom” is specifically for vertical depth measurements. Step-by-Step Solution: Recall definition: fathom is a unit of length used for measuring depth of water.Associate domain: nautical charts mark soundings in fathoms.Select the option that states the specific quantity: depth. Verification / Alternative check: Cross-remember related units: nautical mile for horizontal sea distance; knot for speed; fathom for depth. This triangulation prevents confusion. Why Other Options Are Wrong: sound: a phenomenon, not the measured quantity here. frequency: measured in hertz; unrelated. distance: overly broad; the specialized use is depth. Common Pitfalls: Conflating “distance” and “depth”. Although depth is a length, in maritime usage “fathom” almost always conveys vertical depth. Final Answer: depth

Question 19

Instrumentation – Electric current is measured by which instrument?

Accepted Answer

Introduction / Context: Electrical measurements rely on standard instruments, and knowing which device measures which quantity is foundational for physics, electronics, and engineering labs. This item asks specifically about measuring electric current. Given Data / Assumptions: Sought quantity: electric current (symbol I), typically in amperes (A). We must match it with the correct measuring instrument. Options include both electrical and non-electrical instruments/parts. Concept / Approach: An ammeter is designed to measure current in amperes. In circuits, ammeters are connected in series so that the entire current flows through the meter. Voltmeters, by contrast, measure potential difference and are connected in parallel. Familiarity with these roles prevents wiring errors and instrument damage. Step-by-Step Solution: Identify required measurement: current (A).Recall instrument mapping: current → ammeter; voltage → voltmeter; wind speed → anemometer.Confirm that a commutator is a machine component, not a meter.Select “ammeter”. Verification / Alternative check: Memory aid: names often cue the quantity—“ammeter” (ampere), “voltmeter” (volt), “ohmmeter” (ohm). A multimeter can measure several, but here the single-purpose device is requested. Why Other Options Are Wrong: commutator: part of a DC machine; it reverses current direction, does not measure. anemometer: measures wind speed, not electric current. voltmeter: measures voltage, not current. Common Pitfalls: Confusing ammeter and voltmeter connections (series vs parallel) or assuming any meter can measure all quantities. Final Answer: ammeter

Question 20

Basic Units – One fathom is equal to how much length?

Accepted Answer

Introduction / Context: Nautical measurements frequently use the unit “fathom,” especially for water depth and anchor cables. Knowing the exact equivalence in feet and metres helps convert readings on charts or in maritime reports into familiar units. Given Data / Assumptions: Definition needed: 1 fathom = ? Common conversions: 1 foot = 30.48 cm; 1 m = 100 cm. We compare against feet, metres, and centimetres options. Concept / Approach: By definition, 1 fathom equals 6 feet. Converting to metric: 6 ft * 30.48 cm/ft = 182.88 cm = 1.8288 m. Recognizing this standard avoids confusion with tens-based guesses. Step-by-Step Solution: Start with the standard: 1 fathom = 6 feet.Optional metric check: 6 * 0.3048 m = 1.8288 m.Compare with choices: only “6 feet” matches definition. Verification / Alternative check: Maritime chain lengths and depth soundings are often given in fathoms; sailors historically used armspan approximations close to 6 feet, which aligns with the formal definition. Why Other Options Are Wrong: 6 meters: far too large (≈ 19.7 ft). 60 feet: an order of magnitude off. 100 cm: equals 1 m, not 1.8288 m. Common Pitfalls: Assuming a metric-friendly value due to base-10 familiarity; “fathom” is historical and fixed at 6 feet, not 10 or 100 of anything. Final Answer: 6 feet

General Science Questions