For a 6-input OR gate in combinational logic, identify the single input pattern that yields an output of 0 (logic low).

Introduction / Context:
OR gates produce a logic 1 when any input is 1. The only time an OR gate outputs 0 is when every input is 0. This property generalizes regardless of the number of inputs (2, 4, 6, or more).

Given Data / Assumptions:

• The gate is an ideal 6-input OR.
• Binary inputs are either 0 or 1.
• No wired-logic or inversion is present.

Concept / Approach:
The Boolean expression for an OR gate is Y = A + B + C + D + E + F. Y equals 0 only if A=B=C=D=E=F=0; any single 1 makes Y=1. This aligns with the inclusive definition of the OR operator.

Step-by-Step Solution:

Verification / Alternative check:
Truth tables for OR confirm a single 0-output row where all inputs are 0; all other rows output 1.

Why Other Options Are Wrong:

• 000111, 111000, 111111: each contains ones; the OR outputs 1.
• None of the above: incorrect because 000000 is correct.

Common Pitfalls:
Confusing OR with NOR or assuming exclusive OR semantics; mixing up active-high vs active-low conventions.

Final Answer:
000000