Inlet with leakage (net fill) A tap can fill an empty tank in 12 hours, and a leakage can empty the full tank in 20 hours. If both act together, how long will the tank take to become full?

Difficulty: Easy

Correct Answer: 30 h

Explanation:


Introduction / Context:
A leak is like an outlet with a constant negative rate. With one inlet and one leak, the net rate is inlet minus leak. The fill time is the reciprocal of the net rate.



Given Data / Assumptions:

  • Inlet time = 12 h ⇒ rate = 1/12.
  • Leak time (emptying) = 20 h ⇒ rate = 1/20 (negative).
  • Rates are constant; tank volume is 1 unit.


Concept / Approach:
Net rate = 1/12 − 1/20. Use common denominator to subtract, then invert.



Step-by-Step Solution:

Net rate = 1/12 − 1/20 = (5 − 3) / 60 = 2/60 = 1/30Time to fill = 1 / (1/30) = 30 h


Verification / Alternative check:
In 30 h, the inlet adds 30/12 = 2.5 tanks; the leak removes 30/20 = 1.5 tanks; net = 1 tank.



Why Other Options Are Wrong:
25, 35, 40 produce incorrect net balances when checked.



Common Pitfalls:
Adding times instead of subtracting rates, or miscomputing the common denominator.



Final Answer:
30 h

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