Net rate from volumetric velocities with one outlet Taps A, B, C have velocities 42 L/h, 56 L/h and 48 L/h. A and B are inlets; C is an outlet. If all three are opened together from empty and the tank fills in 16 hours, what is the tank’s capacity?

Introduction / Context:
When volumetric flow rates are given directly, the net inflow is the algebraic sum of the listed L/h values (taking the outlet as negative). Capacity equals net rate multiplied by time to fill.

Given Data / Assumptions:

• A = +42 L/h, B = +56 L/h, C = −48 L/h.
• Tank fills in 16 h.
• Flows are steady and additive.

Concept / Approach:
Net flow = 42 + 56 − 48. Capacity = net flow * time.

Step-by-Step Solution:

Verification / Alternative check:
Reverse check: 800 / 16 = 50 L/h, which equals 42 + 56 − 48.

Why Other Options Are Wrong:
960, 1600, 2346 are inconsistent with the stated time and flows.

Common Pitfalls:
Adding the outlet as positive instead of subtracting.

Final Answer:
800 L