Time for partial fill with three inlets Taps A, B and C fill a tank in 20 min, 15 min and 12 min respectively. If all are opened together, how long will they take to fill 40% of the tank?

Difficulty: Easy

Correct Answer: 2 min

Explanation:


Introduction / Context:
Partial-fill questions use the same rate addition as full-fill problems, but the target volume is a fraction (here 40%) of the tank.



Given Data / Assumptions:

  • A: 20 ⇒ 1/20 per min; B: 15 ⇒ 1/15 per min; C: 12 ⇒ 1/12 per min.
  • All open from empty; target volume = 0.40 tank.


Concept / Approach:
Combined rate = sum of individual rates. Time = (target fraction) / (combined rate).



Step-by-Step Solution:

Combined rate = 1/20 + 1/15 + 1/12 = (3 + 4 + 5) / 60 = 12/60 = 1/5 per minTime for 40% = 0.40 / 0.20 = 2 min


Verification / Alternative check:
In 2 min, they add 2 * (1/5) = 2/5 = 40%.



Why Other Options Are Wrong:
1, 3, 4 min correspond to 20%, 60%, 80% respectively at this rate.



Common Pitfalls:
Computing each tap’s 40% time separately and averaging—incorrect.



Final Answer:
2 min

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