Bacterial exponential growth law: if the specific growth rate μ is constant during the exponential phase, how is cell number concentration Cn related to time (with initial value Cn0 at t0)?

Difficulty: Easy

Correct Answer: Cn = Cn0 * exp[μ * (t - t0)]

Explanation:


Introduction / Context:
During exponential growth, cell populations increase at a rate proportional to their current size. This yields an exponential law widely used to estimate doubling times and to model bioreactor start-up phases. The question asks for the correct mathematical form for cell number concentration Cn over time at constant μ.


Given Data / Assumptions:

  • Specific growth rate μ is constant.
  • Initial condition: Cn = Cn0 at t = t0.
  • No limitations (substrate, oxygen) during the interval.


Concept / Approach:
The differential equation is dCn/dt = μ * Cn. Separating variables and integrating between t0 and t yields ln(Cn/Cn0) = μ * (t − t0), hence Cn = Cn0 * exp[μ * (t − t0)].


Step-by-Step Solution:

1) Write rate law: dCn/dt = μ * Cn.2) Separate and integrate: ∫ dCn/Cn = ∫ μ dt.3) Apply bounds: ln(Cn) − ln(Cn0) = μ (t − t0).4) Exponentiate: Cn = Cn0 * exp[μ (t − t0)].


Verification / Alternative check:
Doubling time td satisfies Cn/Cn0 = 2 = exp(μ td) → td = ln(2)/μ, consistent with standard microbiology.


Why Other Options Are Wrong:

  • Options with 1/μ multipliers: dimensionally inconsistent and not solutions of the differential equation.
  • Linear form Cn = Cn0 + μ (t − t0): describes zero-order growth, not exponential.
  • Cn0 = Cn * exp[…]: rearranged incorrectly.


Common Pitfalls:
Using base-10 instead of natural exponent; forgetting to apply initial conditions leading to missing Cn0 term.


Final Answer:
Cn = Cn0 * exp[μ * (t - t0)]

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