Difficulty: Easy
Correct Answer: All of these: substrate, inhibitory products, and oxygen supply
Explanation:
Introduction / Context:
The specific growth rate μ (per hour) describes how rapidly biomass increases per unit biomass. It is central to Monod-type models and bioreactor design. This question checks your understanding that μ depends on more than just the carbon source, especially in real reactors where inhibition and oxygen transfer constraints appear.
Given Data / Assumptions:
Concept / Approach:
In a simplified Monod model, μ = μ_max * S / (K_s + S). Practical kinetics extend this to include inhibition terms (product inhibition, substrate inhibition) and oxygen limitation (e.g., dependence on dissolved oxygen C_O2 via a saturation function). Hence, μ responds to substrate availability, product buildup, and oxygen transfer/solubility constraints.
Step-by-Step Solution:
Verification / Alternative check:
Chemostat experiments commonly report μ varying with inlet S, aeration/kLa, and product concentration; engineering models incorporate all three.
Why Other Options Are Wrong:
Common Pitfalls:
Overfitting a Monod curve without checking inhibition or oxygen limitation.
Final Answer:
All of these: substrate, inhibitory products, and oxygen supply.
Discussion & Comments