In a batch reactor, how does the specific growth rate μ typically behave over the course of the fermentation (from lag through stationary phases)?

Difficulty: Easy

Correct Answer: It changes during the fermentation as conditions evolve

Explanation:


Introduction / Context:
Batch cultures are closed systems: nutrients deplete, products accumulate, and pH or dissolved oxygen can drift. The specific growth rate μ therefore varies across lag, exponential, deceleration, and stationary phases. This question tests the basic temporal profile of μ in batch operation.


Given Data / Assumptions:

  • No feed or bleed; volume is constant (ignoring evaporation, gas exchange).
  • Substrate and oxygen are finite; products and acids/ethanol may accumulate.
  • Physiology adapts from inoculation to stationary phase.


Concept / Approach:
In lag, μ ≈ 0 while cells adapt. In exponential phase, μ ≈ μ_max if nutrients and O2 are abundant. As limitations and inhibition set in, μ declines. Finally, in stationary phase, net μ approaches 0 as growth balances death or ceases due to depletion/stress.


Step-by-Step Solution:

Lag: enzyme synthesis/adaptation; μ ~ 0.Exponential: μ approaches μ_max.Deceleration: μ falls as S or O2 limit and P accumulates.Stationary: μ ~ 0 (net).


Verification / Alternative check:
Typical growth curves of OD or dry cell weight show sigmoidal behavior consistent with changing μ.


Why Other Options Are Wrong:

  • Constant μ: only holds during a portion of exponential growth.
  • Unbounded exponential: violates resource limits.
  • Highest in stationary: contradictory by definition.
  • Instant drop to zero after inoculation: ignores exponential phase.


Common Pitfalls:
Assuming a single μ fits the whole batch when modeling long runs.


Final Answer:
It changes during the fermentation as conditions evolve.

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