Difficulty: Easy
Correct Answer: proportional to the square of the amplitude
Explanation:
Introduction / Context:
The energy flow in an electromagnetic (EM) wave is described by the Poynting vector. For sinusoidal waves, the time-averaged magnitude (intensity) depends on the amplitudes of the electric and magnetic fields. This question checks whether you know the correct amplitude–energy relationship used throughout optics, antennas, and remote sensing radiometry.
Given Data / Assumptions:
Concept / Approach:
Instantaneous Poynting vector S = E × H. For harmonic waves, the time-average intensity I = is proportional to the product of field amplitudes. Since H0 is proportional to E0 in a given medium, intensity scales as E0^2. Thus, transported energy per unit area per unit time varies with the square of amplitude.
Step-by-Step Solution:
Verification / Alternative check:
Optical irradiance from a source falls off with distance but, at a given point, doubling field amplitude quadruples intensity, consistent with photodetector response in the linear regime.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing field amplitude with power; forgetting that many detectors and link budgets use the square-law relation for EM waves.
Final Answer:
proportional to the square of the amplitude
Discussion & Comments