In an inverting op-amp averaging amplifier, if the feedback resistor Rf equals the value of each input resistor divided by the number of inputs (Rf = Rin/N), what is the resulting relationship between output and the individual input voltages?
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Athe average of the individual inputs
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Bthe inverted sum of the individual inputs
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Cthe sum of the individual inputs
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Dthe inverted average of the individual inputs
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Ethe RMS value of the inputs
Answer
Correct Answer: the inverted average of the individual inputs
Explanation
Introduction:Summing and averaging amplifiers are standard op-amp applications. By choosing resistor ratios appropriately, the same circuit can output a weighted sum, a true average, or a scaled/inverted version of either. This question checks if you can map the resistor relationship onto the mathematical function realized.
Given Data / Assumptions:
- Inverting summing topology with N inputs, each through Rin to the inverting node.
- Feedback resistor Rf set to Rin/N.
- Ideal op-amp, linear region (negative feedback), non-inverting input at ground/reference.
Concept / Approach:For the inverting summer, Vout = −Rf * Σ (Vi / Rin). With Rf = Rin/N, this becomes Vout = −(1/N) * Σ Vi, which is the inverted average of the inputs. If a non-inverted average is desired, a second inverting stage (gain −1) can be added.
Step-by-Step Solution:Start from KCL at virtual ground: Σ (Vi − 0)/Rin = (0 − Vout)/Rf.Rearrange: Vout = −Rf * Σ (Vi / Rin).Substitute Rf = Rin/N: Vout = −(Rin/N) * Σ (Vi / Rin) = −(1/N) * Σ Vi.Interpretation: output equals negative of the arithmetic mean of the inputs.
Verification / Alternative check:Example with N = 4, inputs {1, 2, 3, 4} V gives Σ Vi = 10 V, average = 2.5 V. The circuit outputs −2.5 V, matching the formula. A unity-gain inverter afterward produces +2.5 V if a non-inverted average is required.
Why Other Options Are Wrong:
- Average (non-inverted) / sums: sign or scaling does not match given Rf.
- Inverted sum: would require Rf = Rin (not divided by N).
- RMS: Requires squaring, averaging, and square-root operations, not a simple linear op-amp network.
Common Pitfalls:
- Forgetting the minus sign associated with the inverting input.
- Using unequal Rin values unintentionally, which creates a weighted (not simple) average.
Final Answer:the inverted average of the individual inputs