Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
In first-order active high-pass filters (e.g., op-amp based), the critical frequency establishes where passband behavior begins. Designers often adjust the capacitor to place the cutoff at the desired frequency; understanding the direction of change avoids needless trial and error on the bench.
Given Data / Assumptions:
Concept / Approach:
The cutoff frequency is inversely proportional to the product R * C. Increasing C raises the time constant τ = R * C and therefore reduces f_c. This property lets you shift the corner down in frequency without altering R (useful where R sets bias or noise performance).
Step-by-Step Solution:
Verification / Alternative check:
Example: double C → f_c halves; halve C → f_c doubles. Bode plots confirm the shift along the frequency axis without changing the slope magnitude (±20 dB/decade per pole).
Why Other Options Are Wrong:
Common Pitfalls:
Changing R instead of C and unintentionally altering input bias or source loading; confusing high-pass and low-pass forms.
Final Answer:
Correct
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