Time taken by Ramesh alone = (2/3) x 4 = 8/3 days
? Their 1 day's work = (1/4 + 1/6 + 3/8) = 19/24
So, together they can finish the work in 24 /19 days, i.e., 15/19 days.
? Work of (Ram + Dilip + Shekhar) for 1 day = 1/20
and work of (Ram + Dilip) for 1 day = 1/30
? Work of Shekhar for 1 day = 1 / 20 - 1 / 30 = 1/60
Hence, Shekhar will complete the work in 60 days.
Work completed by A + B in one day = 1/6 + 1/3 = 1/2
? Time taken by A + B to complete the work = 2 days.
Work to be done by C = (1 - 7/11) = 4/11
? (A + B) : C = 7/11 : 4/11 = 7 : 4
? C's share = Rs. 550 x (4/11) = Rs. 200
? One man alone finishes te work in 100 days.
? 10 men can finish the work in 10 day.
? 15 women can finish work in one days = 1/6 - 1/10 = 1/15 work
? 15 women finish the whole work in 15 days
? 1 women finishes the whole work in = 15 x 15 = 225 days
8M + 12W = 4 days (whole work)
? 32M + 48W = 1 day ................ (1)
Again 6M + 14W = 5 days
? 30M + 70W = 1 day ................(2)
From eq. (1) and (2)
32M + 48W = 30M +70W
? 2M = 22W
? 1M = 11W
Now, 30M + 70W = 1 day
(30 X 11 X 70)W = 1 day
Therefore 400W requires 1 day to complete the whole work.
Thus 20W needs 20 days to complete the whole work.
Umesh's 5 day's work = 5 x (1/15) = 1/3
Remaining work = (1 - 1/3) = 2/3
(1/10 + 1/15) work is done by both in 1 day
? 2/3 work is done by both in 6 x (2/3) = 4 days
Hence, the work was completed in 4 + 5 = 9 days.
A's 10 day's work = (10 x 1/80) = 1/8
Remaining work = (1 - 1/8) = 7/8
? 7/8 work is done by B in 42 days
? Whole work will be done by B in (42 x 8/7) = i .e., 48 days.
? (A + B)'s day's work = (1/80 + 1/48) = 8/240 = 1/30
Hence, A and B together can finish it in 30 days.
A's 10 day's work = 10 x (1/25) = 2/5
Remaining work = 1 - 2/5 = 3/5
Work was done by (A + B) in 1 day = (1/25 + 1/20) = 9/100
? 3/5 work was done by (A + B) in (100/9 x 3/5) = 20/3 days
Hence, the work lasted for (10 + 62/3) = 162/3 days.
? In 12 days work done by 14 men = 1
? In 4 days work done by 14 men = 1 x 4/12 = 1/3
? Remaining work = 1 - 1/3 = 2/3
and number of total men = 14 + 2 = 16
If 1 work is done by 14 men in 12 days
? 2/3 work is done by 16 men in 12 x (14/16) x (2/3) = 7 days
12 men can complete 1/3 of the work in 3 days and the remaining 2/3 of the work in 6 days.
1 man can complete 2/3 of the work in (12 x 6) = 72 days
? (12 - 2 + 6) = 16 men can complete 2/3 of thye work in 72/16 = 41/2 days
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.