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- Question
What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { int i, n; char *x="Alice"; n = strlen(x); *x = x[n]; for(i=0; i<=n; i++) { printf("%s ", x); x++; } printf("\n", x); return 0; }
Options- A. Alice
- B. ecilA
- C. Alice lice ice ce e
- D. lice ice ce e
- Correct Answer
- lice ice ce e
ExplanationIf you compile and execute this program in windows platform with Turbo C, it will give "lice ice ce e".It may give different output in other platforms (depends upon compiler and machine). The online C compiler given in this site will give the Option C as output (it runs on Linux platform).
More questions
- 1. It is necessary to call the macro va_end if va_start is called in the function.
Options- A. Yes
- B. No Discuss
Correct Answer: Yes
- 2. Left shifting a number by 1 is always equivalent to multiplying it by 2.
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
0001 => 1
0010 => 2
0100 => 4
1000 => 8
- 3. What will be the output of the program?
#include<stdio.h> int main() { printf("%%%%\n"); return 0; }
Options- A. %%%%%
- B. %%
- C. No output
- D. Error Discuss
Correct Answer: %%
- 4. A function that receives variable number of arguments should use va_arg() to extract arguments from the variable argument list.
Options- A. True
- B. False Discuss
Correct Answer: True
- 5. What will be the output of the program?
#include<stdio.h> int main() { float a = 0.7; if(0.7 > a) printf("Hi\n"); else printf("Hello\n"); return 0; }
Options- A. Hi
- B. Hello
- C. Hi Hello
- D. None of above Discuss
Correct Answer: Hi
Explanation:
if(0.7 > a) here a is a float variable and 0.7 is a double constant. The double constant 0.7 is greater than the float variable a. Hence the if condition is satisfied and it prints 'Hi'
Example:#include<stdio.h> int main() { float a=0.7; printf("%.10f %.10f\n",0.7, a); return 0; }Output:
0.7000000000 0.6999999881- 6. What will be the output of the program (sample.c) given below if it is executed from the command line?
cmd> sample friday tuesday sunday/* sample.c */ #include<stdio.h> int main(int sizeofargv, char *argv[]) { while(sizeofargv) printf("%s", argv[--sizeofargv]); return 0; }
Options- A. sample friday tuesday sunday
- B. sample friday tuesday
- C. sunday tuesday friday sample
- D. sunday tuesday friday Discuss
Correct Answer: sunday tuesday friday sample
- 7. What will be the output of the program (sample.c) given below if it is executed from the command line?
cmd> sample friday tuesday sunday/* sample.c */ #include<stdio.h> int main(int argc, char *argv[]) { printf("%c", *++argv[2] ); return 0; }
Options- A. s
- B. f
- C. u
- D. r Discuss
Correct Answer: u
- 8. Point out the error in the program.
#include<stdio.h> int main() { const int k=7; int *const q=&k; printf("%d", *q); return 0; }
Options- A. Error: RValue required
- B. Error: Lvalue required
- C. Error: cannot convert from 'const int *' to 'int *const'
- D. No error Discuss
Correct Answer: No error
Explanation:
No error. This will produce 7 as output.- 9. Bit fields CANNOT be used in union.
Options- A. True
- B. False Discuss
Correct Answer: False
Explanation:
The following is the example program to explain "using bit fields inside an union".#include<stdio.h> union Point { unsigned int x:4; unsigned int y:4; int res; }; int main() { union Point pt; pt.x = 2; pt.y = 3; pt.res = pt.y; printf("\n The value of res = %d" , pt.res); return 0; } // Output: The value of res = 3- 10. What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog 10 20 30/* myprog.c */ #include<stdio.h> int main(int argc, char **argv) { int i; for(i=0; i<argc; i++) printf("%s\n", argv[i]); return 0; }
Options- A. 10 20 30
- B. myprog 10 20
- C. myprog 10 20 30
- D. 10 20 Discuss
Correct Answer: myprog 10 20 30
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