What will be the output of the program If the integer is 4bytes long? #include int main() { int ***r, **q, *p, i=8; p = &i; q = &p; r = &q; printf("%d, %d, %d ", *p, **q, ***r); return 0; }

Question

What will be the output of the program If the integer is 4bytes long? #include<stdio.h>

int main()
{
    int ***r, **q, *p, i=8;
    p = &i;
    q = &p;
    r = &q;
    printf("%d, %d, %d
", *p, **q, ***r);
    return 0;
}

Accepted Answer

Answer explained in detail.

What will be the output of the program If the integer is 4bytes long? #include<stdio.h> int main() { int r, q, p, i=8; p = &i; q = &p; r = &q; printf("%d, %d, %d\n", p, q, r); return 0; }

Discussion & Comments

What will be the output of the program If the integer is 4bytes long? #include<stdio.h> int main() { int ***r, **q, *p, i=8; p = &i; q = &p; r = &q; printf("%d, %d, %d\n", *p, **q, ***r); return 0; }

Discussion & Comments

What will be the output of the program If the integer is 4bytes long? #include<stdio.h> int main() { int r, q, p, i=8; p = &i; q = &p; r = &q; printf("%d, %d, %d\n", p, q, r); return 0; }