What will be the output of the program if the size of pointer is 4-bytes? #include int main() { printf("%d, %d\n", sizeof(NULL), sizeof("")); return 0; }

2, 1
2, 2
4, 1
4, 2

Correct Answer: 4, 1

Explanation:

In TurboC, the output will be 2, 1 because the size of the pointer is 2 bytes in 16-bit platform.
But in Linux, the output will be 4, 1 because the size of the pointer is 4 bytes.
This difference is due to the platform dependency of C compiler.

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