What will be the output of the program? #include int main() { int arr[3] = {2, 3, 4}; char *p; p = arr; p = (char*)((int*)(p)); printf("%d, ", *p); p = (int*)(p+1); printf("%d", *p); return 0; }

Question

What will be the output of the program? #include<stdio.h>

int main()
{
    int arr[3] = {2, 3, 4};
    char *p;
    p = arr;
    p = (char*)((int*)(p));
    printf("%d, ", *p);
    p = (int*)(p+1);
    printf("%d", *p);
    return 0;
}

Accepted Answer

Answer explained in detail.

What will be the output of the program? #include<stdio.h> int main() { int arr[3] = {2, 3, 4}; char p; p = arr; p = (char)((int)(p)); printf("%d, ", p); p = (int)(p+1); printf("%d", p); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { int arr[3] = {2, 3, 4}; char *p; p = arr; p = (char*)((int*)(p)); printf("%d, ", *p); p = (int*)(p+1); printf("%d", *p); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { int arr[3] = {2, 3, 4}; char p; p = arr; p = (char)((int)(p)); printf("%d, ", p); p = (int)(p+1); printf("%d", p); return 0; }