What will be the output of the program? #include int main() { int x=30, *y, *z; y=&x; /* Assume address of x is 500 and integer is 4 byte size */ z=y; *y++=*z++; x++; printf("x=%d, y=%d, z=%d ", x, y, z); retur…

Question

What will be the output of the program? #include<stdio.h>

int main()
{
    int x=30, *y, *z;
    y=&x; /* Assume address of x is 500 and integer is 4 byte size */
    z=y;
    *y++=*z++;
    x++;
    printf("x=%d, y=%d, z=%d
", x, y, z);
    retur…

Accepted Answer

Answer explained in detail.

What will be the output of the program? #include<stdio.h> int main() { int x=30, y, z; y=&x; /* Assume address of x is 500 and integer is 4 byte size / z=y; y++=*z++; x++; printf("x=%d, y=%d, z=%d\n", x, y, z); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { int x=30, *y, *z; y=&x; /* Assume address of x is 500 and integer is 4 byte size */ z=y; *y++=*z++; x++; printf("x=%d, y=%d, z=%d\n", x, y, z); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { int x=30, y, z; y=&x; /* Assume address of x is 500 and integer is 4 byte size / z=y; y++=*z++; x++; printf("x=%d, y=%d, z=%d\n", x, y, z); return 0; }