A simply supported beam , 6 m long and of effective depth 50 cm, carries a unifo

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Question
A simply supported beam , 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is
Options
A. 14 cm²
B. 15 cm²
C. 16 cm²
D. 17 cm²
E. 18 cm²

Correct Answer

16 cm²

RCC Structures Design problems

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1. Pick up the incorrect statement from the following. The intensity of horizontal shear stress at the elemental part of a beam section, is directly proportional to
Options
A. shear force
B. area of the section
C. distance of the C.G. of the area from its neutral axis
D. moment of the beam section about its neutral axis
E. width of the beam.

3. In a singly reinforced beam, the effective depth is measured from its compression edge to
Options
A. tensile edge
B. tensile reinforcement
C. neutral axis of the beam
D. longitudinal central axis.

6. Pick up the true statement from the following:
Options
A. Plain ceiling provides the best property diffusing light
B. In the absence of beams, it is easier to install piping
C. In the absence of beams, it is easier to paint
D. A flat slab is capable to withstand concentrated loads
E. All the above.

7. If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is
Options
A.
B.
C.
D.
E. All the above.

8. If a rectangular prestressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be
Options
A. 5 cm
B. 10 cm
C. 15 cm
D. 20 cm
E. 25 cm

10. If the permissible compressive and tensile stresses in a singly reinforced beam are 50 kg/cm² and 1400 kg/cm² respectively and the modular ratio is 18, the percentage area At of the steel required for an economic section, is
Options
A. 0.496%
B. 0.596%
C. 0.696%
D. 0.796%
E. none of these.

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