Consider the following

1. Maximum energy of electrons liberated photoelectrically is independent of light intensity
2. Maximum energy of electrons liberated photoelectrically varies nonlinearly with frequency of incident light.

The area of the shaded region

.

Consider

Number of samples per period = 10p

This is not a rational number. Hence signal is non periodic.

? V_P = 3.46 x 10⁸ m/s.

This can be solve by using Boolean identity but using k map it will be more easy

(A + B + C) (A + B + C) (A + B + C).

Here,

a = 1.59'' = 40.386 mm = 4.04 cm

? .

Since number of comparators = 2ⁿ - 1 = 15;

Then number of bits are '4'

Resolution

Use the condition of controllability.

2^{n - 1} R = 32 K&Omeg;

n = 4

? 8R = 32

R = 4 K?.

V₁ = i₁R₁ + i₂R₂

i₁ + ai₁ = i₂

V₂ = i₂R₂

Putting a = - 1

= 0 V.

A quantity of any substance equal to its molecular weight in grams is a mole of that substance contains the same number of molecules as one mole of any other substance. This Avogadro's number and equals 6.02 x 10²³ molecules per mole. Thus

= 9.03 x 10²⁸ electrons/m³

Since for tungsten the atomic and the molecular weights are the same. Therefore for tungsten

E_F = 3.64 x 10^-19(?)^2/3

= 3.64 x 10^{- 19}(9.03 x 10²⁸)^2/3

E_F = 7.326 eV.