A TV picture is to be transmitted over a channel of 6 MHz bandwidth at a 35 dB S/N ratio. The capacity of the channel is

• 50 Mbps
• 100 Mbps
• 36 Mbps
• 72 Mbps

Correct Answer: 72 Mbps

Explanation:

W = B = Bandwidth

C = 6 x 10⁶ x 12 = 72 Mbps.