Difficulty: Easy
Correct Answer: A two-span conjugate beam of the same length with end pins/rollers kept as pins/rollers, fixed ends (if any) changed to free ends, and an INTERNAL SIMPLE SUPPORT placed exactly at the real beam’s internal hinge
Explanation:
Introduction / Context:The conjugate beam method transforms a bending problem into a statics problem by mapping the real beam to a conjugate beam whose shear and reactions represent slopes and deflections. Correctly creating the conjugate beam support conditions is essential; otherwise, the computed slopes and deflections will be wrong.
Given Data / Assumptions:
Concept / Approach:
Mapping rules are: (1) a fixed end in the real beam becomes a free end in the conjugate beam; (2) a pin/roller support at an end remains a pin/roller at the same end in the conjugate beam; (3) an internal hinge in the real beam becomes an internal simple support in the conjugate beam. The loading on the conjugate beam is the M/EI diagram of the real beam; the conjugate-beam reactions correspond to real-beam rotations/deflections.
Step-by-Step Solution:
Identify supports in the real beam (fixed/pinned/roller) and apply the mapping to each end.Locate the internal hinge in the real beam and replace it with an internal simple support in the conjugate beam.Keep end pins/rollers unchanged, convert fixed ends to free ends, and insert the internal support at the hinge location.Select the option that follows exactly this construction.Verification / Alternative check:
At internal hinges, the real beam allows moment release (zero moment, finite rotation). In the conjugate beam, this state is modeled by a simple support (zero deflection, free slope reaction analogy), validating the mapping.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
A two-span conjugate beam of the same length with end pins/rollers kept as pins/rollers, fixed ends (if any) changed to free ends, and an INTERNAL SIMPLE SUPPORT placed exactly at the real beam’s internal hinge
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