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- Question
What was the day of the week on 28th May, 2006?
Options- A. Thursday
- B. Friday
- C. Saturday
- D. Sunday
- Correct Answer
- Sunday
Explanation
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.
Given day is Sunday.
- 1. How many days are there in x weeks x days?
Options- A. 7x2
- B. 8x
- C. 14x
- D. 7 Discuss
- 2. What will be the day of the week 15th August, 2010?
Options- A. Sunday
- B. Monday
- C. Tuesday
- D. Friday Discuss
- 3. The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Options- A. 4.37%
- B. 5%
- C. 6%
- D. 8.75% Discuss
- 4. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
Options- A. 57%
- B. 60%
- C. 65%
- D. 90% Discuss
- 5. If A = x% of y and B = y% of x, then which of the following is true?
Options- A. A is smaller than B.
- B. A is greater than B
- C. Relationship between A and B cannot be determined.
- D. If x is smaller than y, then A is greater than B.
- E. None of these Discuss
- 6. Today is Monday. After 61 days, it will be:
Options- A. Wednesday
- B. Saturday
- C. Tuesday
- D. Thursday Discuss
- 7. The calendar for the year 2007 will be the same for the year:
Options- A. 2014
- B. 2016
- C. 2017
- D. 2018 Discuss
- 8. The last day of a century cannot be
Options- A. Monday
- B. Wednesday
- C. Tuesday
- D. Friday Discuss
- 9. What was the day of the week on 17th June, 1998?
Options- A. Monday
- B. Tuesday
- C. Wednesday
- D. Thursday Discuss
- 10. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options- A. Sunday
- B. Saturday
- C. Tuesday
- D. Wednesday Discuss
Calendar problems
Search Results
Correct Answer: 8x
Explanation:
x weeks x days = (7 x + x ) days = 8 x days.
Correct Answer: Sunday
Explanation:
15 th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
∴ 227 days = (32 weeks + 3 days) ≡ 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.
Given day is Sunday.
Correct Answer: 5%
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = | ❨ | 87500 | x 100 | ❩% = 50%. |
| 175000 |
| ∴ Required average = | ❨ | 50 | ❩% = 5%. |
| 10 |
Correct Answer: 57%
Explanation:
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
| ∴ Required percentage = | ❨ | 11628 | x 100 | ❩% = 57%. |
| 20400 |
Correct Answer: None of these
Explanation:
| x% of y = | ❨ | x | x y | ❩ | = | ❨ | y | x x | ❩ | = y% of x |
| 100 | 100 |
∴ A = B.
Correct Answer: Saturday
Explanation:
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
∴ After 61 days, it will be Saturday.
Correct Answer: 2018
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days ≡ 0 odd days.
∴ Calendar for the year 2018 will be the same as for the year 2007.
Correct Answer: Tuesday
Explanation:
100 years contain 5 odd days.
∴ Last day of 1st century is Friday.
200 years contain (5 x 2) ≡ 3 odd days.
∴ Last day of 2nd century is Wednesday.
300 years contain (5 x 3) = 15 ≡ 1 odd day.
∴ Last day of 3rd century is Monday.
400 years contain 0 odd day.
∴ Last day of 4th century is Sunday.
This cycle is repeated.
∴ Last day of a century cannot be Tuesday or Thursday or Saturday.
Correct Answer: Wednesday
Explanation:
17 th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) ≡ 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
∴ 168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Correct Answer: Sunday
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
∴ The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
∴ 6th March, 2004 is Sunday (1 day before to 6th March, 2005).
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