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- Question
What was the day of the week on 28th May, 2006?
Options- A. Thursday
- B. Friday
- C. Saturday
- D. Sunday
- Correct Answer
- Sunday
Explanation
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.
Given day is Sunday.
- 1. A man can row 9 1/ 3 in still water and he finds that it takes him thrice as much time to row up than as to row down the same distance in river. The speed of the current is?
Options- A. 31 / 3 km/hr
- B. 31/3 km/hr
- C. 11/4 km/hr
- D. 42/3 km/hr Discuss
- 2. The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year ?
Options- A. Rs. 1100
- B. Rs. 1200
- C. Rs. 1000
- D. Rs. 1840 Discuss
- 3. Find: S.l. on Rs 3000 at 18% per annum for the period from 4th
Options- A. 118
- B. 105
- C. 108
- D. 110 Discuss
- 4. Arun took a loan of Rs. 29000 with simple interest for as many years as the rate of interest. If he paid Rs. 10440 as interest at the end of the loan period, what was the rate of interest?
Options- A. 5.5%
- B. 6%
- C. 6.5%
- D. 7% Discuss
- 5. A Certain sum of money an amounts to Rs 2500 in a span Of 5 years and further to Rs.3000 in a span of 7 years at simple interest The sum is ?
Options- A. Rs. 1800
- B. Rs. 2000
- C. Rs. 1400
- D. Rs. 1250 Discuss
- 6. A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is:
Options- A. 5%
- B. 8%
- C. 12%
- D. 15% Discuss
- 7. The total simple interest earned on a sum of money increases by Rs. 600 when the rate of interest increases by 2% per annum. If the investment was made for 5 years, find the sum of money that was invested ?
Options- A. Rs. 6000
- B. Rs. 5550
- C. Rs. 7500
- D. Rs. 6580 Discuss
- 8. A boat has to travel upstream 20 km distance from point X of a river to points Y. The total time taken by boat in travelling from point X to Y and Y to X is 41 min 40 s. What is the speed of the boat?
Options- A. 66 km/h
- B. 72 km/h
- C. 48 km/h
- D. Cannot be determined Discuss
- 9. Gopal borrowed some money at 12% simple interest. If he had to pay back Rs. 1280 after 5 years, in order to clear off the loan. How much did he borrow?
Options- A. Rs. 800
- B. Rs. 620
- C. Rs. 560
- D. Rs. 480 Discuss
- 10. A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. What is the rate of interest
Options- A. 3%
- B. 4%
- C. 5%
- D. 6% Discuss
More questions
Correct Answer: 42/3 km/hr
Explanation:
Let speed upstream = x km/hr
Then, speed downstream = 3x km/hr
? Speed in still water = (x + 3x)/2 km/hr = 2x km/hr
Speed of the current = (3x - x)/2 km/hr = x km/hr
&becaus 2x = 28/3
? x = 14/3 = 42/3 km/hr.
Correct Answer: Rs. 1200
Explanation:
P --- 10 ----- 600
P --- 5 ----- 300
3P --- 5 ----- 900
__________
1200
Correct Answer: 108
Explanation:
(24 + 31 + 18) days = 73 days = 1/5 year .
P = Rs 3000 and R = 18 % p.a.
Correct Answer: 6%
Explanation:
Principle amount = Rs. 29000
Interest = Rs. 10440
Let rate of interest = r%
=> So, time = r years
According to the question,
10440 = 29000 x r x r/100
290 x r x r = 10440
r x r = 1044/29 = 36
r = 6
Hence, the rate of interest = 6% and time = 6 yrs.
Correct Answer: Rs. 1250
Explanation:
2500 in 5th year and 3000 in 7th year
So in between 2 years Rs. 500 is increased => for a year 500/2 = 250
So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250
Hence, the initial amount must be 2500 - 1250 = Rs. 1250
Correct Answer: 12%
Explanation:
S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.
S.I. for 5 years = Rs. = Rs.3675
Principle = Rs.(9800-3675) = Rs.6125
Hence, Rate = =12%
Correct Answer: Rs. 6000
Explanation:
Let the sum invested be Rs. P
Let the rate of interest be R% per annum
=> Interest earned for 5 years = (P x 5 x R/100) = PR/20
Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%
=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100
Hence,
PR/20 + 10P/100 = PR/20 + 600
=> P = 6000
Therefore, the sum invested is Rs. 6000
Correct Answer: Cannot be determined
Explanation:
Let x be the speed of the boat and y be the speed of the current.
Speed upstream = (x - y) km/h
Speed downstream = (x + y) km/h
According to the question,
20 /(x - y) + 20/(x + y) = 25/36
In this equation, there are two variables but only one equation. So, the value of x cannot be determined.
Correct Answer: Rs. 800
Explanation:
Let the principle amount be Rs. P
Interest rate = 12%
Total amount he paid after 5 years = Rs. 1280
ATQ,
Hence, the amount he borrowed = P = Rs. 800.
Correct Answer: 6%
Explanation:
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = % = 6%
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