Find the next future year (closest to 1991) that has exactly the same calendar as the year 1991. (Assume the Gregorian calendar and matching of weekdays/leap-status.)

Introduction / Context:
Two years share the same calendar if they start on the same weekday and are both leap years or both common years. Calendar repetition depends on how weekday shifts accumulate across common and leap years.

Given Data / Assumptions:

• 1991 is a common (non-leap) year.
• In a common year, the next year starts one weekday later; in a leap year, the following year starts two weekdays later.
• 1992 is leap, so the shift from 1991→1992→1993 involves +1 then +2 weekday steps across that boundary.

Concept / Approach:
For a common year followed immediately by a leap year, the same calendar typically repeats after 6 years. Therefore, 1991 will match 1997 (both common, same weekday alignment).

Step-by-Step Solution:

Verification / Alternative check:
Checking weekday of January 1 and leap status confirms 1997 aligns with 1991; intervening years do not meet both conditions simultaneously.

Why Other Options Are Wrong:
1992 and 1996 are leap years; 1995 starts on a different weekday and does not match all dates. Hence they cannot match 1991’s full calendar.

Common Pitfalls:
Assuming a fixed 7-year cycle for all years; not accounting for the extra shift caused by leap years that immediately follow a common year.

Final Answer:
1997.