The area of the plot can be determined from both I and II as follows .
Let the breadth of the plot be x metres Then, length = (x + 4) metres
Thus, perimeter s 208 metres 2(x + 4 + x) = 208 ,
4x =200, x = 50.
So. length =54 metres. breadth = 50 metres.
Area of the plot = 2700 m^2.
Hence, both I and II are required
All Except `Raft' are down by animal.
Only '729' is a perfect cube.
This is the only prime number in the group.
All others are soild metals.
Former is the food for latter.
As, 4 : 9 similarly 8 : 13
? ? = 13
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.