Each of the questions below consists of a question and three statements numbered I, II and III given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read the question and all three statements and give answer accordingly. Six employees E, F, G, H, I, J attend office on six different days starting from Monday to Saturday and each of them have their office on different floors viz. 1st, 4th, 5th, 6th, 8th, 9th. The one who has office on 1st floor attend office on which of the following day? I. Only two persons attend office in between G and H. The one who attend office on Wednesday has office on 8th floor. F has office on an even numbered floor. E attends the office immediately before I. G attends office before H and has office on an odd numbered floor. II. No one attend office after J. Only three persons attend office in between the one who has office on 1st floor and the one who has office on 5th floor. The one who attend office immediately before I has office 1st floor. III. G has office neither on 1st nor on 5th floor. F attends office immediately after H. The one who attend office on Thursday does not has office on 4th floor.

### Concept & Logic Data Sufficiency involving linear scheduling and arrangement. The goal is to determine if the given statements logically lock the day for the person on the 1st floor without needing to completely solve the entire puzzle. ### Step-by-Step Solution **Analyze Statement I:** - $G$ attends before $H$ with exactly two persons between them. - Wednesday = 8th floor. - $E$ is immediately before $I$. - $F$ is on an even floor; $G$ is on an odd floor. - *Conclusion:* Not sufficient alone. **Analyze Statement II:** - $J$ is the last person, meaning $J$ attends on Saturday. - Three persons are between the 1st floor and the 5th floor. - The person attending immediately before $I$ has the 1st floor. - *Conclusion:* Not sufficient alone. **Combine Statements I and II:** - From II, $J$ is on Saturday, so the remaining days are Monday to Friday. - From I, there are two spaces between $G$ and $H$. The only possible slots for $(G, H)$ in the Monday–Friday window are (Monday, Thursday) or (Tuesday, Friday). - Let's test (Tuesday, Friday) for $G$ and $H$: - The remaining consecutive days for the $E$ and $I$ block would be Wednesday and Thursday. So, $E$ = Wednesday, $I$ = Thursday. - However, II states the person before $I$ (which is $E$) has the 1st floor. But I states Wednesday is the 8th floor. This is a direct contradiction ($1 \neq 8$). - Therefore, $G$ must be on Monday and $H$ on Thursday. - The remaining consecutive days for the $E$ and $I$ block must be Tuesday and Wednesday. So, $E$ is on Tuesday and $I$ is on Wednesday. - From II, the person before $I$ ($E$ on Tuesday) has the 1st floor. - We have definitively found that the person on the 1st floor attends on **Tuesday** using only Statements I and II. ### Exam Strategy & Shortcut In Data Sufficiency, stop solving the moment you prove a unique answer exists. Since Statements I and II force $E$ to be on Tuesday and confirm $E$ is on the 1st floor, Statement III is completely unnecessary. Do not waste time figuring out the exact floors of the other employees. ### Common Pitfall A common mistake is assuming you must find the complete schedule for all six employees to answer the question. You only need to verify if the specific question asked can be definitively answered. ### Final Answer Therefore, the correct answer is **If the data in statement I and II together are sufficient to answer the question, while the data in statement III are not required to answer the question.**