Definition of a digital quantity: does it assume discrete values? Evaluate the statement: “A digital quantity has a discrete set of values.” Decide whether this captures the essence of digital representation.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Digital versus analog is a core distinction in engineering. A digital quantity is one that assumes values from a countable set, typically finite within a given word length. This item checks your understanding of that definition and its implications for measurement and computation.



Given Data / Assumptions:

  • Digital systems represent information with discrete symbols (bits) aggregated into words.
  • A fixed word length implies a finite set of representable codes at any instant.
  • Quantization maps continuous variables to discrete codes.


Concept / Approach:
By definition, digital quantities are discrete. An n-bit word encodes 2^n possible values (or states). In contrast, analog quantities vary continuously within ranges. The discreteness underpins quantization error, sampling theory, and noise immunity advantages of digital processing.



Step-by-Step Solution:

Differentiate digital (discrete) from analog (continuous).Relate to word length: n bits → 2^n representable codes.Recognize effects: quantization error and stepwise resolution.Conclude the statement is correct.


Verification / Alternative check:
Consider a 10-bit ADC: it outputs one of 1024 codes for any input, illustrating discreteness.



Why Other Options Are Wrong:

Incorrect: Opposes the fundamental definition.Voltage/time/frequency qualifiers: Discreteness applies to the represented variable regardless of domain; sampling in time is also discrete when clocked.


Common Pitfalls:
Assuming digital waveforms are “square analog” and thus continuous; their representation and interpretation are discrete even if the physical waveform has finite rise time.



Final Answer:
Correct

More Questions from Digital Concepts

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion