Difficulty: Medium
Correct Answer: One of the inputs to the active-LOW select AND gate may be stuck high for some reason; take both select lines LOW and check for pulse activity on the outputs, Q0–Q3. If the outputs now respond, the problem is most likely in the program or circuitry driving the select lines.
Explanation:
Introduction / Context:
When a memory’s data outputs remain at a constant logic level, the fault may be within the device or in the external selection/enable logic. Understanding active-LOW chip-select behavior and how it gates the internal read path is key to isolating the issue quickly.
Given Data / Assumptions:
Concept / Approach:
If any input to an active-LOW select AND gate is held HIGH, the device never asserts its internal output drivers, regardless of address activity. Therefore, a stuck-HIGH select input can fully explain “outputs always LOW.” A practical test is to force both select lines LOW and observe whether Q0–Q3 now show activity; if they do, the device is likely fine and the fault lies upstream in the select-driving logic or code.
Step-by-Step Solution:
Verification / Alternative check:
Compare by probing the enable pins relative to datasheet truth table; if enable never satisfies the active condition, static outputs are expected. Additional check: inspect OE/CE/WE polarity and timing.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
One select input stuck HIGH preventing chip enable; force both selects LOW to test. If outputs then respond, the external select-driving circuitry is at fault.
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