C++ object lifetime: constructor prints "Curious", destructor prints "Tab" — what is the output?\n\n#include <iostream.h>\nclass CuriousTab {\npublic:\n CuriousTab() { cout << "Curious"; }\n ~CuriousTab() { cout << "Tab"; }\n};\nint main() {\n CuriousTab objTab; // automatic object\n return 0; // destructor runs at scope end\n}\n

Introduction / Context:
This question checks understanding of automatic storage duration and the order of constructor/destructor calls in C++. Output is produced first by the constructor and then by the destructor when the object goes out of scope at the end of main.

Given Data / Assumptions:

• Constructor writes "Curious".
• Destructor writes "Tab".
• objTab is a local object in main.

Concept / Approach:
For an automatic object, construction occurs upon entering the block and destruction occurs on leaving it. Thus, the concatenated stream shows constructor text followed by destructor text without a newline: "CuriousTab".

Step-by-Step Solution:

Verification / Alternative check:
Allocating with new would print only the constructor text unless delete is called; here, automatic storage ensures destructor runs.

Why Other Options Are Wrong:

• Curious or Tab alone: ignores either construction or destruction.
• Compile error: code is valid with classic headers.

Common Pitfalls:
Expecting a newline or space between outputs; misunderstanding when destructors execute for automatic variables.

Final Answer:
The program will print the output CuriousTab.