C++ object lifetime: constructor prints "Curious", destructor prints "Tab" — what is the output? #include class CuriousTab { public: CuriousTab() { cout << "Curious"; } ~CuriousTab() { cout << "Tab"; } }; int main() { CuriousTab objTab; // automatic object return 0; // destructor runs at scope end }

Introduction / Context: This question checks understanding of automatic storage duration and the order of constructor/destructor calls in C++. Output is produced first by the constructor and then by the destructor when the object goes out of scope at the end of main.

Given Data / Assumptions:

• Constructor writes "Curious".
• Destructor writes "Tab".
• objTab is a local object in main.

Concept / Approach: For an automatic object, construction occurs upon entering the block and destruction occurs on leaving it. Thus, the concatenated stream shows constructor text followed by destructor text without a newline: "CuriousTab".

Step-by-Step Solution:

Verification / Alternative check: Allocating with new would print only the constructor text unless delete is called; here, automatic storage ensures destructor runs.

Why Other Options Are Wrong:

• Curious or Tab alone: ignores either construction or destruction.
• Compile error: code is valid with classic headers.

Common Pitfalls: Expecting a newline or space between outputs; misunderstanding when destructors execute for automatic variables.

Final Answer: The program will print the output CuriousTab.