C++ (inheritance, default arguments, and overrides) — track member initialization and outputs with pre/post operators.\n\n#include<iostream.h>\nclass CuriousTabBase {\npublic:\n int x, y;\n CuriousTabBase(int xx = 0, int yy = 5) { x = ++xx; y = --yy; }\n void Display() { cout << --y; }\n ~CuriousTabBase() {}\n};\nclass CuriousTabDerived : public CuriousTabBase {\npublic:\n void Increment() { y++; }\n void Display() { cout << --y; }\n};\nint main(){\n CuriousTabDerived objCuriousTab; // uses base default ctor\n objCuriousTab.Increment();\n objCuriousTab.Display();\n return 0;\n}\n\nWhat is printed?

Introduction / Context:
This question tests default argument handling in a base constructor and how pre/post operators affect state across member functions, including an override of Display() in the derived class.

Given Data / Assumptions:

• Base constructor runs with defaults xx = 0, yy = 5.
• In constructor: x = ++xx → 1; y = --yy → 4.
• Derived adds Increment() → y++.
• Derived overrides Display() to print --y.

Concept / Approach:
Trace the member y across operations in order: initialization, increment, and pre-decrement during display. The code never uses the base Display(); it uses the override in the derived type, operating on the same y member inherited from the base.

Step-by-Step Solution:

Verification / Alternative check:
If you instead called the base Display() (e.g., objCuriousTab.CuriousTabBase::Display()), the same calculation would occur since both versions print --y.

Why Other Options Are Wrong:

• 3 or 5: Off-by-one due to misreading pre/post semantics.
• Garbage/compile error: All members are initialized and types valid.

Common Pitfalls:
Forgetting that ++ and -- change the stored value, not just the printed value.

Final Answer:
4