C++ (overload resolution with char literal among short/int/float constructors) — which message is printed?\n\n#include<iostream.h>\nclass CuriousTab {\n int x;\npublic:\n CuriousTab(short) { cout << "Short" << endl; }\n CuriousTab(int) { cout << "Int" << endl; }\n CuriousTab(float) { cout << "Float" << endl; }\n ~CuriousTab() { cout << "Final"; }\n};\nint main(){ CuriousTab* ptr = new CuriousTab('B'); return 0; }\n\nAssume there is no delete.

Introduction / Context:
With overloads for short, int, and float, a character literal is passed. C++ applies standard conversion sequences and ranks them to choose the best overload. The destructor message will not appear because the allocated object is never deleted.

Given Data / Assumptions:

• Overloads: (short), (int), (float).
• Argument: char literal 'B'.
• No delete → destructor not called.

Concept / Approach:
Integral promotions promote types narrower than int to int (or unsigned int). char is promoted to int as part of the integral promotions. A promotion to int is a better conversion sequence than a conversion to short (which is not a promotion) or to float (a floating conversion). Therefore, the (int) constructor is selected and prints "Int".

Step-by-Step Solution:

Verification / Alternative check:
Cast to (short)'B' to force "Short"; cast to 66.0f to see "Float".

Why Other Options Are Wrong:

• Short/Float: Worse conversion ranks than promotion to int.
• Final: Requires delete or scope exit for an automatic object.

Common Pitfalls:
Assuming char selects the char overload (which does not exist here) or that short is preferred for small integers over int.

Final Answer:
The program will print the output Int .