C++ constructor prints a character from a float via char(yy): what appears on the console?\n\n#include <iostream.h>\nclass CuriousTab {\n int x;\npublic:\n CuriousTab(int xx, float yy) { cout << char(yy); }\n};\nint main() {\n CuriousTab *p = new CuriousTab(35, 99.50f);\n return 0;\n}\n

Introduction / Context:
The constructor converts a float to char and streams it to cout. In standard C++ streaming, writing a char outputs the corresponding character, not the numeric code. Here, 99.50f is converted to an implementation-defined char by truncation toward zero (commonly 99), which corresponds to the ASCII character 'c'.

Given Data / Assumptions:

• yy = 99.50f; char(yy) converts to a char with code approximately 99.
• cout << char outputs the character itself.
• No newline or numeric formatting is applied.

Concept / Approach:
Numeric to char conversion takes the integer part of the float (implementation-defined if outside range; within range here) and interprets that code as a character. ASCII 99 corresponds to 'c', so the visible console output is the single character c (not "99" or "99.50").

Step-by-Step Solution:

Verification / Alternative check:
Replacing cout << char(yy) with cout << int(yy) would print 99 numerically; using cout << yy would print 99.5 with default formatting.

Why Other Options Are Wrong:

• 99 / 99.50: numeric printing, which is not what cout does for char.
• Garbage value: the value is well-defined and within range.

Common Pitfalls:
Expecting cout to display the numeric code when streaming a char; forgetting that casting to unsigned char and then to int is required to print the code number portably.

Final Answer:
ASCII value of 99