C++ (constructor overload resolution) — which constructor is called for a character literal created via new, and what is printed?\n\n#include<iostream.h>\nclass CuriousTab {\n int x;\npublic:\n CuriousTab(short) { cout << "Short" << endl; }\n CuriousTab(int) { cout << "Int" << endl; }\n CuriousTab(char) { cout << "Char" << endl; }\n ~CuriousTab() { cout << "Final"; }\n};\nint main() {\n CuriousTab* ptr = new CuriousTab('B');\n return 0;\n}\n\nAssume no delete is performed.

Introduction / Context:
This question checks C++ overload resolution and object lifetime when allocating with new without a corresponding delete. Multiple constructors accept integral-like parameters, and a character literal is passed. Which overload is a best match?

Given Data / Assumptions:

• Overloads: (short), (int), and (char).
• Call is new CuriousTab('B').
• No delete; therefore the destructor message "Final" will not be printed in this run.

Concept / Approach:
Overload resolution prefers the exact match over promotions or conversions. The argument 'B' has type char, so the constructor CuriousTab(char) is an exact match. Short or int would require a conversion/promotion that is strictly worse than an exact match.

Step-by-Step Solution:

Verification / Alternative check:
Change the literal to 66 (an int) and you will see "Int". Use (short)'B' to force "Short".

Why Other Options Are Wrong:

• Short / Int: Not selected because an exact char match exists.
• Final: Destructor is not invoked without delete.
• None of the above: A listed option is correct.

Common Pitfalls:
Confusing integral promotions with exact matches, and expecting destructors to run for leaked objects at program end.

Final Answer:
The program will print the output Char .