Number systems conversion (digital electronics): convert the decimal value 89 (base 10) to its exact binary representation (base 2). Which of the following choices correctly equals 89 in binary?

Difficulty: Easy

Correct Answer: 1011001₂

Explanation:


Introduction / Context:
Converting between decimal (base 10) and binary (base 2) is a foundational skill in digital electronics and computer architecture. The question asks for the binary representation of 89₁₀. Understanding this helps with addressing, masking, and low-level data manipulations.


Given Data / Assumptions:

  • Target value: 89 in base 10.
  • Binary uses powers of 2 (… 64, 32, 16, 8, 4, 2, 1).
  • No sign bit or fractional components are involved.


Concept / Approach:
The standard approach is repeated subtraction (or division by 2 remainders) using powers of 2. Express 89 as a sum of distinct powers of 2, then place 1s in those bit positions and 0s elsewhere. Highest power of 2 not exceeding 89 is 64 (2^6).


Step-by-Step Solution:

Identify powers: 89 - 64 = 25 → bit for 2^6 is 1. Next: 25 - 16 = 9 → bit for 2^4 is 1 (2^5 = 32 is too large, so bit 2^5 is 0). Next: 9 - 8 = 1 → bit for 2^3 is 1. Remaining: 1 → bit for 2^0 is 1. Bits for 2^2 and 2^1 are 0. Assemble bits from 2^6 to 2^0: 1 0 1 1 0 0 1 → 1011001₂.


Verification / Alternative check:
Compute 1011001₂ back to decimal: 64 + 16 + 8 + 1 = 89. This confirms correctness.


Why Other Options Are Wrong:

1011011₂ = 64 + 16 + 8 + 2 + 1 = 91 (not 89). 1100111₂ = 64 + 32 + 4 + 2 + 1 = 103 (not 89). 10011₂ = 16 + 2 + 1 = 19 (too small). “None of the above” is incorrect because a correct option exists.


Common Pitfalls:
Dropping leading zeros is fine, but do not drop necessary middle zeros; confusing the order of bits or mis-summing powers of 2 causes off-by-one errors.


Final Answer:
1011001₂

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