Parity and XOR behavior: an XOR gate (extended to multiple inputs) asserts logic-1 for input words containing how many 1-bits?

Difficulty: Easy

Correct Answer: odd

Explanation:


Introduction / Context:
XOR (exclusive-OR) is central to parity computations and error detection. When generalized to more than two inputs, XOR outputs 1 precisely when the count of 1-bits at its inputs is odd.


Given Data / Assumptions:

  • XOR is associative and commutative over binary inputs.
  • Multiple-input XOR equals 1 if an odd number of inputs are 1.
  • Even number of 1s yields 0.


Concept / Approach:
Define XOR truth for two inputs: 0⊕0=0, 0⊕1=1, 1⊕0=1, 1⊕1=0. Extending iteratively shows that XOR acts as a parity detector: it toggles with each encountered 1.


Step-by-Step Solution:

Consider a running XOR starting from 0. Each 1 flips the state; each 0 leaves it unchanged. Odd flips end at 1; even flips end at 0 → odd parity detection.


Verification / Alternative check:
Test examples: with three inputs 1,1,1 → 1⊕1⊕1 = 1; with four 1s → 1⊕1⊕1⊕1 = 0.


Why Other Options Are Wrong:

Even: XOR output is 0 for even count of 1s. “Different” is vague and does not precisely describe parity behavior. “All of the above” contradicts the unique parity rule.


Common Pitfalls:
Confusing XOR with OR; OR outputs 1 when any input is 1, regardless of parity.


Final Answer:
odd

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