Question 1

What do the following declaration signify? char *arr[10];

Accepted Answer

arr is a array of 10 character pointers.

Question 2

What do the following declaration signify? int (*pf)();

Accepted Answer

pf is a pointer to a function which return int

Question 3

Declare the following statement? "An array of three pointers to chars".

Accepted Answer

char *ptr[3];

Question 4

What do the following declaration signify? int *f();

Accepted Answer

f is a function returning pointer to an int.

Question 5

Declare the following statement? "A pointer to a function which receives an int pointer and returns float pointer".

Accepted Answer

float *(*ptr)(int*)

Question 6

What do the following declaration signify? char **argv;

Accepted Answer

argv is a pointer to a char pointer.

Question 7

Declare the following statement? "A pointer to a function which receives nothing and returns nothing".

Accepted Answer

void (*ptr)()

Question 8

What do the following declaration signify? char *scr;

Accepted Answer

scr is a pointer to char.

Question 9

What do the following declaration signify? void *cmp();

Accepted Answer

cmp is a function that return a void pointer.

Question 10

Declare the following statement? "A pointer to an array of three chars".

Accepted Answer

char (*ptr)[3];

Question 11

What do the following declaration signify? void (*cmp)();

Accepted Answer

cmp is a pointer to a function which returns void .

Question 12

What do the following declaration signify? int *ptr[30];

Accepted Answer

ptr is a array of 30 pointers to integers.

Question 13

What will be the output of the program in Turbo C? #include<stdio.h>

int main()
{
    char near *near *ptr1;
    char near *far *ptr2;
    char near *huge *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
    return 0;
}

Accepted Answer

2, 4, 4

Question 14

What will be the output of the program? #include<stdio.h>

int main()
{
    char huge *near *ptr1;
    char huge *far *ptr2;
    char huge *huge *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
    return 0;
}

Accepted Answer

2, 4, 4

Question 15

What will be the output of the program (in Turbo C under DOS)? #include<stdio.h>

int main()
{
    char huge *near *far *ptr1;
    char near *far *huge *ptr2;
    char far *huge *near *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(ptr2), siz…

Accepted Answer

4, 4, 2

Question 16

What will be the output of the program under DOS? #include<stdio.h>

int main()
{
    char huge *near *far *ptr1;
    char near *far *huge *ptr2;
    char far *huge *near *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3));…

Accepted Answer

4, 2, 2

Question 17

What will be the output of the program? #include<stdio.h>

int main()
{
    char far *near *ptr1;
    char far *far *ptr2;
    char far *huge *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
    return 0;
}

Accepted Answer

2, 4, 4

Question 18

What will be the output of the program? #include<stdio.h>

int main()
{
    char huge *near *far *ptr1;
    char near *far *huge *ptr2;
    char far *huge *near *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3));
…

Accepted Answer

4, 4, 4

Question 19

What will be the output of the program? #include<stdio.h>
typedef void v;
typedef int i;

int main()
{
    v fun(i, i);
    fun(2, 3);
    return 0;
}
v fun(i a, i b)
{
    i s=2;
    float i;
    printf("%d,", sizeof(i));
    printf(…

Accepted Answer

4, 12

Question 20

What will be the output of the program? #include<stdio.h>
typedef unsigned long int uli;
typedef uli u;

int main()
{
    uli a;
    u b = -1;
    a = -1;
    printf("%lu, %lu", a, b);
    return 0;
}

Accepted Answer

The system will treat the negative numbers with 2's complement method. For 'long int' system will occupy 4 bytes (32 bits). Therefore, Binary 1 : 00000000 00000000 00000000 00000001 To represent -1, system uses the 2's complement value of 1. Add 1 to the 1's complement result to obtain 2's complement of 1. So, First take 1's complement of binary 1 (change all 0s to 1s and all 1s to 0s) 1's complement of Binary 1: 11111111 11111111 11111111 11111110 2's complement of Binary 1: (Add 1 with the above result) 11111111 11111111 11111111 11111111 In HexaDecimal 11111111 11111111 11111111 11111111 = FFFF FFFF FFFF FFFF In Unsigned Integer 11111111 11111111 11111111 11111111 = 4294967295.

Complicated Declarations Questions