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What will be the output of the program under DOS? #include int main() { char huge near far ptr1; char near far huge ptr2; char far huge near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }

4, 4, 4
4, 2, 2
2, 8, 4
2, 4, 8

Correct Answer: 4, 2, 2

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More Questions from Complicated Declarations

What will be the output of the program? #include int main() { char far *near *ptr1; char far *far *ptr2; char far *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program? #include int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3)); return 0; }
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What will be the output of the program in DOS (Compiler - Turbo C)? #include double i; int main() { (int)(float)(char) i; printf("%d", sizeof((int)(float)(char)i)); return 0; }
What will be the output of the program? #include int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(**ptr1), sizeof(ptr2), sizeof(*ptr3)); return 0; }
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