What will be the output of the program under DOS? #include int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d ", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3));…

Question

What will be the output of the program under DOS? #include<stdio.h>

int main()
{
    char huge *near *far *ptr1;
    char near *far *huge *ptr2;
    char far *huge *near *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3));…

Accepted Answer

Answer explained in detail.

What will be the output of the program under DOS? #include<stdio.h> int main() { char huge near far ptr1; char near far huge ptr2; char far huge near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }

Discussion & Comments

What will be the output of the program under DOS? #include<stdio.h> int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }

Discussion & Comments

What will be the output of the program under DOS? #include<stdio.h> int main() { char huge near far ptr1; char near far huge ptr2; char far huge near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }