What will be the output of the program? #include int main() { char far *near *ptr1; char far *far *ptr2; char far *huge *ptr3; printf("%d, %d, %d ", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }

Question

What will be the output of the program? #include<stdio.h>

int main()
{
    char far *near *ptr1;
    char far *far *ptr2;
    char far *huge *ptr3;
    printf("%d, %d, %d
", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
    return 0;
}

Accepted Answer

Answer explained in detail.

What will be the output of the program? #include<stdio.h> int main() { char far near ptr1; char far far ptr2; char far huge ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { char far *near *ptr1; char far *far *ptr2; char far *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int main() { char far near ptr1; char far far ptr2; char far huge ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }