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Complicated Declarations
What do the following declaration signify? void *cmp();
cmp is a pointer to an void type.
cmp is a void type pointer variable.
cmp is a function that return a void pointer.
cmp function returns nothing.
Correct Answer:
cmp is a function that return a void pointer.
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Complicated Declarations
Declare the following statement? "A pointer to an array of three chars".
What do the following declaration signify? void (*cmp)();
What do the following declaration signify? int *ptr[30];
What will be the output of the program in Turbo C? #include
int main() { char near *near *ptr1; char near *far *ptr2; char near *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program? #include
int main() { char huge *near *ptr1; char huge *far *ptr2; char huge *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program (in Turbo C under DOS)? #include
int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program under DOS? #include
int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program? #include
int main() { char far *near *ptr1; char far *far *ptr2; char far *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
What will be the output of the program? #include
int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3)); return 0; }
What will be the output of the program? #include
typedef void v; typedef int i; int main() { v fun(i, i); fun(2, 3); return 0; } v fun(i a, i b) { i s=2; float i; printf("%d,", sizeof(i)); printf(" %d", a*b*s); }
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